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3 years ago

I wanted to knwo what two to the third power was please help

Mathematics

2 answers:

nikitadnepr [17]3 years ago

8 0

Eight is the answer.

Dmitry_Shevchenko [17]3 years ago

6 0

You can use your default calculator for these problems. However, you can also do it in your head! Exponents are just a number times its self a certain amount of times.

So, 2^3 is 2 * 2 * 2. What would that equal?

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Which expressions are equivalent??

Brilliant_brown [7]

<u>Given</u>:

The given expression is $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$

We need to determine the equivalent expression.

<u>Option A:</u> -1

Solving the expression, we get;

$\frac{3}{2} x+14-\frac{3}{2} x+15$

Simplifying, we get;

$14+15=29$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is not equivalent to -1.

Hence, Option A is not the correct answer.

<u>Option B</u>: 29

Solving the expression, we get;

$\frac{3}{2} x+14-\frac{3}{2} x+15$

Simplifying, we get;

$14+15=29$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to 29.

Hence, Option B is the correct answer.

<u>Option C</u>: $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Let us rewrite the given expression.

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, Option C is the correct answer.

<u>Option D</u>: $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Rewriting the expression, we get;

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent not to $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Thus, Option D is not the correct answer.

<u>Option E:</u> $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Multiplying the terms within the bracket, we get;

$2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Thus, Option E is the correct answer.

4 0

2 years ago

Rewrite the fraction in the sentence below as a percentage. In 2002, a popular company made 11/20 of its money online.

Vladimir79 [104]

Answer:

55%

Step-by-step explanation:

11/20 = 0.55

0.55 = 55%

7 0

2 years ago

WILL GIVE BRAINLIST!<br> Which set of ordered pairs shows a functional relationship?

MaRussiya [10]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Please help!!

Misha Larkins [42]

Its 26.315% or rounded to 26.32% commission

Explanation; you take the total of the car, and then divide that by the exact amount Ken earned leaving you with the commission

18,250 ÷ 693.50 = 26.315789474 (normally using only the first two decimals when counting money, rounded to the nearest tenth) leaving you with 26.32

5 0

2 years ago

(a) The position of a particle at time t is s(t) = t^3 + t. Compute the average velocity over the time interval [7, 12].(b) Esti

ryzh [129]

Answer:

<h2>a) Average velocity = 278 units</h2><h2>b) Instantaneous velocity at t = 7 seconds is 148 units</h2>

Step-by-step explanation:

a) Average velocity is the ratio of displacement to time.

We have

s(t) = t³ + t

t is in between 7 and 12

s(7) = 7³ + 7 = 350

s(12) = 12³ + 12 = 1740

Displacement = 1740 - 350 = 1390

Time = 12 - 7 = 5

Displacement = Average velocity x time

1390 = Average velocity x 5

Average velocity = 278 units

b) s(t) = t³ + t

Differentiating

v(t) = 3t² + 1

At t = 7

v(t) = 3 x 7² + 1 = 148 units

Instantaneous velocity at t = 7 seconds is 148 units

8 0

3 years ago