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Rudik [331]
3 years ago
5

Write one number that is a factor 13.

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

1

Step-by-step explanation:

This is because 13 is a primary number

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We are given two sides of a triangle that are 2 and 5 and the angle between them is pi/3 or 60 degrees. In this case, we can use the cosine law to relate the given dimensions and angle. The cosine rule goes c2 = a2 + b2 - 2abcos C; Substituting, c2 = 4 + 25 - 2*2*5*cos pi/3 ; c2 = 19; c = sqrt 19 = 4.36 units.
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I’m an idiot and bad at linear please help
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zero slope

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3 years ago
What is the volume of A cube with the surface area of 600 in.²
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Answer:

1000 in³

Step-by-step explanation:

A cube has 6 square faces

Given the surface area of the cube = 600 in², then

The area of 1 face = 600 ÷ 6 = 100 in²

The area of a square = s² ( where s is the measure of a side ), thus

s² = 100 ( take the square root of both sides )

s = \sqrt{100} = 10

The volume (V) of the cube = s³, so

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8 0
4 years ago
Someone help me asap​
Taya2010 [7]

Answer:

$12.25

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6 0
3 years ago
Larry and Paul start out running at a rate of 5 mph. Paul speeds up his pace after 5 miles to 10 mph but Larry continues the sam
klasskru [66]
<h2>Hello!</h2>

The answer is:

They will be 10 miles apart after 3 hours.

<h2>Why?</h2>

To calculate how long after they start will they be 10 miles apart, we need to assume that after 1 one hour, they were at the same distance (5 miles), then, calculate the time when they are 10 miles apart, knowing that Paul increased its speed two times, running first at 5mph and then, at 10 mph.

The time that will pass to be 10 miles apart can be calculated using the following equation:

TotalTime=TimeToReach5miles+TimeToBe10milesApart

Calculating the time to reach 5 miles for both Larry and Paul, at a speed of 5 mph, we have:

x=xo+v*t\\\\5miles=0+5mph*t\\\\t=\frac{5miles}{5mph}=1hour

We have that to reach a distance of 5 miles, they needed 1 hour. We need to remember that at this time, they were at the same distance.

If we want to know how many time will it take for them to be 10 miles apart with Paul increasing its speed to 10mph, we need to assume that after that time, the distance reached by Paul will be the distance reached by Larry plus 10 miles.

So, for the second moment (Paul increasing his speed) we have:

For Larry:

x_{L}=5miles+5mph*t

Therefore, the distance of Paul will be equal to the distance of Larry plus 10 miles.

For Paul:

x{L}+10miles=xo+10mph*t\\\\5miles+5mph*t+10miles=5miles+10mph*t\\\\5miles+10miles-5miles=10mph*t-5mph*t\\\\10miles=5mph*t\\\\t=\frac{10miles}{5mph}=2hours

Then, there will take 2 hours to Paul to be 10 miles apart from Larry after both were at 5 miles and Paul increased his speed to 10 mph.

Hence, calculating the total time, we have:

TotalTime=TimeToReach5miles+TimeToBe10milesApart

TotalTime=1hour+2hours=3hours

Have a nice day!

3 0
4 years ago
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