The domain for the function f(x) = |x + 1| is the set of all real numbers.
The range of the function is the set of positive real numbers.
Given the function f(x) = |x + 1|
f(-4) = |-4 + 1| = | -3| = 3
This means that the number -4 is at a distance of 3 units away from -1 on the number line.
f(2) = |2 + 1| = |3| = 3
This means that the number 2 is at a distance of 3 units away from -1 on the number line.
f(1.5) = |1.5 + 1| = |2.5| = 2.5
This means that the number 1.5 is at a distance of 2.5 units away from -1 on the number line.
Learn more at:
Domain and range - brainly.com/question/2264373
Absolute value or modulus function - brainly.com/question/12980508
#SPJ9
Answer: FIRST OPTION
Step-by-step explanation:
<h3>
The missing picture is attached.</h3>
By definition, given a Quadratic equation in the form:
Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.
The Quadratic Formula is the following:
In this case, the exercise gives you this Quadratic equation:
You can identify that the numerical coefficients are:
Therefore, you can substitute values into the Quadratic formula shown above:
You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.
Answer:
Step-by-step explanation:
g(-2)=2(-2)^3+3(-2)^2-3(-2)+4=-16+12+6+4=6
g(-1)=2(-1)^3+3(-1)^2-3(-1)+4=-2+3+3+4=8
it does not change sign ,so there is no real zero between -2 and -1.
Answer:
12.77
Step-by-step explanation:
Answer:
202
Step-by-step explanation:
4th answer