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Zinaida [17]
3 years ago
12

use the intermediate value theorem to determine, if possible, whether g(x)=2x^3+3x^2-3x+4 has a real zero between -2 and -1

Mathematics
1 answer:
inn [45]3 years ago
3 0

Answer:

Step-by-step explanation:

g(-2)=2(-2)^3+3(-2)^2-3(-2)+4=-16+12+6+4=6

g(-1)=2(-1)^3+3(-1)^2-3(-1)+4=-2+3+3+4=8

it does  not change sign ,so there is no real zero between -2 and -1.

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First term ,a=4 , common difference =4-7=-3, n =50
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derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

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Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
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