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3 years ago

use the intermediate value theorem to determine, if possible, whether g(x)=2x^3+3x^2-3x+4 has a real zero between -2 and -1

Mathematics

1 answer:

inn [45]3 years ago

3 0

Answer:

Step-by-step explanation:

g(-2)=2(-2)^3+3(-2)^2-3(-2)+4=-16+12+6+4=6

g(-1)=2(-1)^3+3(-1)^2-3(-1)+4=-2+3+3+4=8

it does not change sign ,so there is no real zero between -2 and -1.

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grigory [225]

$9x^{2} + 4y^{2} =144$
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