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Zinaida [17]
3 years ago
12

use the intermediate value theorem to determine, if possible, whether g(x)=2x^3+3x^2-3x+4 has a real zero between -2 and -1

Mathematics
1 answer:
inn [45]3 years ago
3 0

Answer:

Step-by-step explanation:

g(-2)=2(-2)^3+3(-2)^2-3(-2)+4=-16+12+6+4=6

g(-1)=2(-1)^3+3(-1)^2-3(-1)+4=-2+3+3+4=8

it does  not change sign ,so there is no real zero between -2 and -1.

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<h3>What is a graph?</h3>
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brainly.com/question/16608196

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