A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&M's, & 3 Butterfingers. What is the probability o

Question

2 years ago

9

f selecting some M&M's, putting them back, and then selecting a Butterfinger?

1 answer:

a_sh-v [17] · Answer 1 · 2022-07-31T22:11:45+03:00

Answer:

2/27

Step-by-step explanation:

In the question we have:

4 snickers

2 packages of M&M's

3 Butterfingers.

Total number of candies in the Halloween bag = 9

Probability of selecting some M&M's and putting them back = 2/9

Probability of selecting a Butter finger = 3/9

Therefore, the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger =

Probability of selecting some M&M's and putting them back × Probability of selecting a Butter finger

2/9 × 3/9

= 6/ 81

= 2/27