Yeah there is a way... Lemme give a typical question...
Find the common difference of an arithmetic progression whose first term Is 1 and last term is 1023...
First term = T¹ =a
Last term = Tn = a + (n-1)d
Since your given the values of the first and the last term... You can substitute
Tn = 1 + (1023-1)d
1023 = 1 + 1022d
1022d = 1023 - 1
1022d = 1022
common difference = 1...
So there is a way....
You can get the common difference using the two terms given...
Hope this helped...
400,400,200,800,200,300,70,100
Answer:
1, 3, 19, 57, 361, and 1083.
Step-by-step explanation:
5/7. You are eliminating one of the 8 original lockers yet you still have 5 possible stars left. Hence a probability of 5 stars over 7 possible lockers left. 5/7 = .7143 or 71.43 %
Step-by-step explanation:
The table of three and x is common
So
3x ( x + 5)
Is the answer