All categories

3 years ago

What is the probability of rolling an odd number on a number cube and flipping a coin landing on tails?

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

7 0

Answer: 1/4

Step-by-step explanation: take the odds of the first event (1/2) and the odds of the second event (1/2) and multiply them together

MariettaO [177]3 years ago

5 0

The answer is 1/4

3/6 of the numbers on the cube are odd, so simplify that to 1/2.

you have a 1/2 chance of getting tails when you flip a coin.

you multiply 1/2 X 1/2= 1/4

You might be interested in

There are 9 people going on a trip. They purchased coach tickets for $160, and first class tickets for $1180. The total budget t

Savatey [412]

Answer:

Step-by-step explanation:

Given

There are 9 people going on a trip

They purchased coach tickets =$160

first class tickets =$1180

total budget to spend = $4500

Let coach tickets=X

So first class tickets=9-x

160x+1180(9-x)=4500

160+10620-1180x=4500

160x-1180x=4500-10620

-1020x=-6120

X=6120/1020

X=6

So answer

Coach tickets=X=6

First class tickets=(9-x)

=3.

4 0

3 years ago

Identify the variables in the graph describe how the variables are related

Alex17521 [72]

The time(h), would be the independent variable and the temperature(C) would be the dependent variable.

3 0

3 years ago

Maggie's brother is 4 years younger than three times her age. The sum of their ages is 16.

bearhunter [10]

Answer:

Maggie is 5 years old

Step-by-step explanation:

3M-4+M=16

add 4 to both sides

4M=20

Divide both sides by 4

20/4 = 5

M/Maggie is 5

7 0

3 years ago

A car was Skid to a half a uniform rate of -9.4 m/s ^2 squared if the measure skid marks that are 34 m long with what speed is t

babymother [125]

Answer:

vi = 25.28 m/s

Step-by-step explanation:

a = -9.4 m/s²

x = 34 m

vf = 0 m/s

vi = ?

We can apply the equation

vf² = vi² + 2*a*x

⇒ vi = √(vf² - 2*a*x)

⇒ vi = √((0 m/s)² - 2*(-9.4 m/s²)*34 m)

⇒ vi = 25.28 m/s

5 0

3 years ago

CONDITIONAL PROBABILITY URGENT?

diamong [38]

WE need to find the probability ( $\frac{Junior}{Boy}$

We know $P(\frac{A}{B})= \frac{P(A and B)}{P(B)}$

P( $\frac{Junior}{Boy}$ )= $\frac{P(Junior and Boy)}{(Boy)}$

First we find P(Boy)

From the table we can see that we have 12 boys out of (12+18=30) students

So P(Boy) = $\frac{12}{30}$

Now we find the intersection of Junior and Boy

WE look at the Junior row and boys column that is 2

{P(Junior ∩ Boy) = $\frac{2}{30}$

P( $\frac{Junior}{Boy}$ )= $\frac{P(Junior and Boy)}{(Boy)}$

P( $\frac{Junior}{Boy}$ )= $\frac{\frac{2}{30}}{\frac{12}{30}}$

= $\frac{2}{12}$ = $\frac{1}{6}$

P( $\frac{Junior}{Boy}$ ) = $\frac{1}{6}$

4 0

3 years ago