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matrenka [14]
3 years ago
5

Extra points! Help me if y’all can! Thanks so much!!

Mathematics
1 answer:
Aliun [14]3 years ago
5 0
I believe it is: 212

y2-y1 / x2-x1
549-125 / 5-3
212
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Option 1

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BRAINLIEST!!!!!
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you talk on the phone y minutes on a day x of every month according to the equation y=2x+1. The cellphone company claims you tal
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Please need help urgent
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Answers with explanations:

Problem 2-
First we have to insert our numbers into the equation. So we would have
l2l-l-7l
The ll bars mean to find the absolute value. Absolute value is how many spaces it is between that number and zero. So we can simply this to
2-7=-5

Problem 3-
First, we have to insert our numbers into the problem.
2(-2)^3(3)
Using PEMDAS or order of operations, we solve the exponent first and simplify from there
2(-8)(3)
(-16)(3)
(-48)
The answer is -48

Problem 4-
Again, we have to input the numbers into the equation.
(4^2-4(-3))/2
(16-4(-3))/2
(16+12)/2
(28)/2
14
The answer is 14

Problem 5-
(3)(-1)-(-1^2)
(3)(-1)-(1)
-3-1
-4
The answer is -4

Problem 7-
l-3-4l- -3^2
l-3-4l- +9
l-7| - +9
7-+9
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The answer is -2

Problem 8-
3(-3)^2-4|-3|+6
3(9)-4|-3|+6
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21
3 0
3 years ago
Clue #1: The sum of the digits of a 3 digit number is 20. Clue #2: The tens digit is 2 less than the hundreds digit. Clue #3: Th
o-na [289]

Answer: The number is 974

Step-by-step explanation:

First, any 3 digit number can be written as:

N = a*100 + b*10 + c

Where a, b, and c are single-digit numbers.

a is the hundreds digit

b is the tens digit

c is the unit digit

We can write the clues as:

#1: a + b + c = 20

#2: b = a - 2

#3: c = a + b - 12

Then we have a system of equations:

a + b + c = 20

b = a - 2

c = a + b - 12

To solve this, we need to isolate one of the variables in one equation and then replace this in the other equations, we can see that b is already isolated in the second equation, then we can replace that in the first and third equations:

a + (a - 2) + c = 20

c = a + (a - 2) - 12

Now we can see that c is isolated in the second equation, then we can replace that in the first one to get:

a + (a - 2) + (a + (a - 2) - 12) = 20

Now we can solve this for a:

a + a - 2 + a + a -2 - 12 = 20

4*a - 16 = 20

4*a = 20 + 16

4*a = 36

a = 36/4 = 9

With this, we can find the values of b and c.

b = a - 2 = 9 - 2 = 7

c = a + b - 12 = 9 + 7 - 12 = 4

Then the 3-digit number is:

N = a*100 + b*10 + c = 9*100 + 7*10 + 4 = 974

N = 974

6 0
3 years ago
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