3 years ago

F(x)=3x^2-x+2; [-3,1]

Mathematics

1 answer:

laiz [17]3 years ago

6 0

Is it written like this?

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What is the value of m, if the equation my2+2y−4=0 has exactly one root?

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Answer:

$m=\frac{-1}{4}$

Step-by-step explanation:

A quadratic equation has one root if the discriminant is 0.

That is we need $b^2-4ac=0$ for this particular question.

Compare the following to find $a,b, \text{ and } c$ :

$ax^2+bx+c=0$

$my^2+2y-4=0$

The variable $x$ is representative of the variable $y$ here.

$a=m$

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Plug in into $b^2-4ac=0$ :

$(2)^2-4(m)(-4)=0$

$4+16m=0$

Subtract 4 on both sides:

$16m=-4$

Divide both sides by 16:

$m=\frac{-4}{16}$

Reduce:

$m=\frac{-1}{4}$

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