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2 years ago

Which of the following is not a solution for x < 8?

1 answer:

4 0

X = 9 is the only choice that is not a solution.

Explanation:
7.95, 4.3, and -3 are all values that are less than 8. For instance, if you were to plot these values on a number line, 9 would be the only value to the right of 8 or the only value that surpasses 8.

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Miss Riley's class has 24 students. She has the students in groups. Each group can have no more than 5 students. if every studen

netineya [11]

Answer:

if there can be no more than 5 students, then anything less than 5 students will suffice. However we don’t want any left over ones cause we don’t want that one kid sitting alone during lunch so we can simply put 4 into each group.

Step-by-step explanation:

Hope this helped :DDD

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1 year ago

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Multiplying Binomials

ch4aika [34]

Answer:

Concept: Binomial Multiplication

(x-1)(x-9)
x^2-9x-x+9
x^2-10x+9

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2 years ago

Equation of a line with slip of 5 passing through points (-4,-6)

kirill [66]

$\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=5[x-(-4)] \\\\\\ y+6=5(x+4)\implies y+6=5x+4\implies y=5x-2$

5 0

2 years ago

I need help, does anyone understand this?

Mama L [17]

a so-called zero or solution is really just an x-intercept, in which case we set the dependent variable to 0, namely y = h(x) = 0 and solve for x to get it.

$\bf h(x)=4x^2-8x-60\implies \stackrel{h(x)}{0}=4x^2-8x-60\implies \stackrel{\textit{dividing by 4}}{0=x^2-2x-15} \\\\\\ 0=(x-5)(x+3)\implies x= \begin{cases} 5\\ \boxed{-3} \end{cases}$

why is -3 the smallest? well, -3 is much smaller than 5 :), the further to the left you go on the number line, the smaller the number.

4 0

2 years ago

Read 2 more answers

Assume the random variable X is normally distributed with mean 53 and standard deviation of 6. Find the 9th percentile

satela [25.4K]

Answer:

The 9th percentile of X is 44.96

Step-by-step explanation:

Percentiles for a Normal Distribution

The standard normal distribution can be used for computing percentiles. For example, the median is the 50th percentile being the center value, the first quartile is the 25th percentile, and so on.

To compute percentiles of a normal distribution we can use the formula

$X=\mu+z\sigma$

Where $\mu$ is the mean, $\sigma$ is the standard deviation of the variable X, and z is the z-score value from the standard tables

The value of X can also be directly obtained from digital tables included in math packages and tools like Excel.

The Excel NORM.INV Function calculates the inverse of the cumulative Normal Distribution Function for a given value of p, $\mu$ and $\sigma$ .

We'll use the values

$p=9\%=0.09,\ \mu=53, \ \sigma=6$

NORM.INV(0.09,53,6) results in 44.96 which means the 9th percentile of X is 44.96

We could have used the standard normal distribution, which only needs the value of p

$NORM.S.INV( 0.09 )=-1.34$

That is the value of z, we now apply the formula

$X=\mu+z\sigma$

$X=53+(-1.34)\cdot 6=44.96$

We get the very same result as before

6 0

2 years ago