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2 years ago

Which of the following is not a solution for x < 8?

1 answer:

4 0

X = 9 is the only choice that is not a solution.

Explanation:
7.95, 4.3, and -3 are all values that are less than 8. For instance, if you were to plot these values on a number line, 9 would be the only value to the right of 8 or the only value that surpasses 8.

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4 1/9 - 3 3/5 what is the answer to this question ?

Sindrei [870]

The answer is 0.51111111111111111 (It goes on for infinity).

8 0

2 years ago

Find the missing values<br> 3:4=6:__=9:_=12:_=15:_

Dahasolnce [82]

Step-by-step explanation:

6:8=9:12=12:16=15:20

5 0

2 years ago

Factorise 2p^2 - p - 10<br> (2p squared)

velikii [3]

2p² - p - 10 = 0

2 = a

- 1 = b

- 10 = c

To factor, find two numbers that multiply to equal a·c and also that have a sum of b

2p² + 4p - 5p - 10 = 0

2p (p + 2) - 5 (p + 2) = 0

<h3>Answer: ( 2p - 5 ) ( p + 2 ) = 0</h3>

3 0

2 years ago

What is the factored form of x^3 -1

lianna [129]

Answer:

The factored form of x^3 -1 will be:

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

Step-by-step explanation:

Given the expression

$x^3-1$

Rewrite 1 as 1³

$=x^3-1^3$

$\mathrm{Apply\:Difference\:of\:Cubes\:Formula:\:}x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)$

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

$=\left(x-1\right)\left(x^2+x+1\right)$

Thus, the factored form of x^3 -1 will be:

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

8 0

2 years ago

The graph below represents a population

Nataliya [291]

Answer:

Average rate of change for the function for the interval (6, 12] is 500 people per year.

Option A is correct.

Step-by-step explanation:

We need to find the average rate of change for the function for the interval

(6, 12]

The formula used to calculate Average rate of change is:

$Average \ rate \ of \ change=\frac{f(b)-f(a)}{b-a}$

We are given a=6 and b=12

Looking at the graph we can see that when x=6 y= 3000 so, f(a)=3000

and when x=12, y=6000 so, f(b)=6000

Putting values in formula and finding Average rate of change:

$Average \ rate \ of \ change=\frac{f(b)-f(a)}{b-a}\\Average \ rate \ of \ change=\frac{6000-3000}{12-6}\\Average \ rate \ of \ change=\frac{3000}{6}\\Average \ rate \ of \ change=500$

So, average rate of change for the function for the interval (6, 12] is 500 people per year.

Option A is correct.

6 0

2 years ago