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galina1969 [7]
3 years ago
8

Identify the independent and dependent variables in the following y=4x+1

Mathematics
1 answer:
evablogger [386]3 years ago
5 0
I know my sibling wil answer it
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Pls help asap!!!<br><br><br><br> Solve for x . 2x=y
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What does 9n-2&lt;7+20 equal?​
ikadub [295]

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n

n ≈ 3

Step-by-step explanation:

9n-2<7+20

9n-2

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3 years ago
Write the equation of the line of the line that passes through the point (3, -6) and a slope of 5
muminat

Answer:

y=5x-21

Step-by-step explanation:

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Divide using LONG Division<br> (m? + 2m - 15) + (m + 5)
user100 [1]

Answer:

I hope you got it and it helped you

7 0
3 years ago
You use a line of best fit for a set of data to make a prediction about an unknown value. the correlation coeffecient is -0.833
alina1380 [7]

Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2  = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.

Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2  = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.

5 0
3 years ago
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