Answer:
15. Area of parallelogram = bh
b = 9m
h = 4m
a = 9*4 = 36m^2
You can also use the rectangle property here.
a = l*b
l = 9
b = 6
a = 9*6 = 54 m^2
Though I would prefer the first one better.
16. Area of triangle = 1/2*bh
b = 17m
h = 3
a = 17*3/2 = 51/2 = 25.5m^2
18. Area of a trapezium = a+b/2*h (a and b are two parallel sides and h the height)
a = 15
b = 7
h = 15
a = 15+7/2*15 = 22/2*15 = 11*15 = 165m^2
19. Area of triangle = 1/2*bh
b = 24
h = 7
a = 24*7/2 = 168/2 = 84
Hope u understood
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A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
Answer:
yes, you are right, that hexagon follows all of the guidelines
Step-by-step explanation:
wait no, plot points at the correct ones, then draw line straight down, then a reflection of the initial line. Draw points for the corresponding sides
The answer will come out to 30.2
Hi! The temperature would be 18°.
There was a 4 hour period between 5 and 9 a.m.
So, I just took -10, and added 7 four times.
-10 + 7 + 7 + 7 + 7 = 18
Hope this helps you! Happy thanksgiving, here's a turkey!