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drek231 [11]
3 years ago
8

Lindsay is buying an iPad that was originally $500 but is now a discount 45% of what is her new discount price

Mathematics
1 answer:
serg [7]3 years ago
3 0

Answer:

answer: $225

Step-by-step explanation:

500 dollars

45% off

you have to change the r5 into a decimal

(always us the discout go divide by 100)

45/100

.45

$500×.45=$225

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Amy and Zach each have 24 feet of fencing for their rectangular gardens. Amy makes her fence 6 feet long . Zach makes his fence
saul85 [17]

For this case we have that by definition, the area of a rectangle is given by:

A = w * l

Where:

w: Is the width of the rectangle

l: is the length of the rectangle

Each of the girls has 24 feet of fencing, that is, the perimeter is P = 2w + 2l = 24.

Amy:

l = 6 \ ft\\2w + 2 (l) = 24\\2w + 2 (6) = 24\\2w + 12 = 24\\2w = 24-12\\2w = 12\\w = 6

Thus, Amy's fence area is: A = 6 * 6 = 36 \ ft ^ 2

Zach:

l = 8 \ ft\\2w + 2l = 24\\2w + 2 (8) = 24\\2w + 16 = 24\\2w = 24-16\\2w = 8\\w = 4

Thus, the area of Zach's fence is:A = 4 * 8 = 32 \ ft ^ 2

Answer:

Amy's garden has a greater area

36 \ ft ^ 2-32 \ ft ^ 2 = 4ft ^ 2, is 4 \ ft ^ 2greater

5 0
4 years ago
Read 2 more answers
the equation of the line / is -3y+4x=9. write the equation of a line that is parallel to the line / and passes through the point
nekit [7.7K]

Hey!

So before trying to figure out the equation of the line, lets change -3y+4x = 9 into slope-intercept form:

-3y + 4x = 9

-3y = -4x + 9

y = (4/3)x - 3

Now that you have the equation in slope-intercept form we can find the equation of the line parallel to this. One thing that we are given from this equation is the slope of the line, the slope for two parallel lines are the same. So we know that the slope of the line is 4/3. We are also given another point on the line and we can plug this point in for y and x to find the y-intercept or b:

6 = (4/3)(-12) + b

6 = -16 + b

22 = b

Now that we know b, we have both the y-intercept and the slope so our equation would be:

y = (4/3)x + 22

4 0
3 years ago
Pretty easy
Gnom [1K]
$63.2 80% of 79 = 63.2
5 0
3 years ago
What is the derivative of x times squaareo rot of x+ 6?
Dafna1 [17]
Hey there, hope I can help!

\mathrm{Apply\:the\:Product\:Rule}: \left(f\cdot g\right)^'=f^'\cdot g+f\cdot g^'
f=x,\:g=\sqrt{x+6} \ \textgreater \  \frac{d}{dx}\left(x\right)\sqrt{x+6}+\frac{d}{dx}\left(\sqrt{x+6}\right)x \ \textgreater \  \frac{d}{dx}\left(x\right) \ \textgreater \  1

\frac{d}{dx}\left(\sqrt{x+6}\right) \ \textgreater \  \mathrm{Apply\:the\:chain\:rule}: \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx} \ \textgreater \  =\sqrt{u},\:\:u=x+6
\frac{d}{du}\left(\sqrt{u}\right)\frac{d}{dx}\left(x+6\right)

\frac{d}{du}\left(\sqrt{u}\right) \ \textgreater \  \mathrm{Apply\:radical\:rule}: \sqrt{a}=a^{\frac{1}{2}} \ \textgreater \  \frac{d}{du}\left(u^{\frac{1}{2}}\right)
\mathrm{Apply\:the\:Power\:Rule}: \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1} \ \textgreater \  \frac{1}{2}u^{\frac{1}{2}-1} \ \textgreater \  Simplify \ \textgreater \  \frac{1}{2\sqrt{u}}

\frac{d}{dx}\left(x+6\right) \ \textgreater \  \mathrm{Apply\:the\:Sum/Difference\:Rule}: \left(f\pm g\right)^'=f^'\pm g^'
\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(6\right)

\frac{d}{dx}\left(x\right) \ \textgreater \  1
\frac{d}{dx}\left(6\right) \ \textgreater \  0

\frac{1}{2\sqrt{u}}\cdot \:1 \ \textgreater \  \mathrm{Substitute\:back}\:u=x+6 \ \textgreater \  \frac{1}{2\sqrt{x+6}}\cdot \:1 \ \textgreater \  Simplify \ \textgreater \  \frac{1}{2\sqrt{x+6}}

1\cdot \sqrt{x+6}+\frac{1}{2\sqrt{x+6}}x \ \textgreater \  Simplify

1\cdot \sqrt{x+6} \ \textgreater \  \sqrt{x+6}
\frac{1}{2\sqrt{x+6}}x \ \textgreater \  \frac{x}{2\sqrt{x+6}}
\sqrt{x+6}+\frac{x}{2\sqrt{x+6}}

\mathrm{Convert\:element\:to\:fraction}: \sqrt{x+6}=\frac{\sqrt{x+6}}{1} \ \textgreater \  \frac{x}{2\sqrt{x+6}}+\frac{\sqrt{x+6}}{1}

Find the LCD
2\sqrt{x+6} \ \textgreater \  \mathrm{Adjust\:Fractions\:based\:on\:the\:LCD} \ \textgreater \  \frac{x}{2\sqrt{x+6}}+\frac{\sqrt{x+6}\cdot \:2\sqrt{x+6}}{2\sqrt{x+6}}

Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions
\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \  \frac{x+2\sqrt{x+6}\sqrt{x+6}}{2\sqrt{x+6}}

x+2\sqrt{x+6}\sqrt{x+6} \ \textgreater \  \mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c}
\sqrt{x+6}\sqrt{x+6}=\:\left(x+6\right)^{\frac{1}{2}+\frac{1}{2}}=\:\left(x+6\right)^1=\:x+6 \ \textgreater \  x+2\left(x+6\right)
\frac{x+2\left(x+6\right)}{2\sqrt{x+6}}

x+2\left(x+6\right) \ \textgreater \  2\left(x+6\right) \ \textgreater \  2\cdot \:x+2\cdot \:6 \ \textgreater \  2x+12 \ \textgreater \  x+2x+12
3x+12

Therefore the derivative of the given equation is
\frac{3x+12}{2\sqrt{x+6}}

Hope this helps!
8 0
3 years ago
Which ordered pair describes point P? <br> A) -2, +4 <br> B) -2, -4 <br> C) +4, -2<br> D) -4, -2 
zimovet [89]
The answer is a.  (-2, 4). The horizontal line is the x-axis, and the vertical line is the y-axis, so the coordinate points would be (x, y) and (-2, 4) fit those coordinates. Hope this helps! :)
7 0
3 years ago
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