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2 years ago

Elsie saved the money from her summer job. In

Mathematics

1 answer:

Mumz [18]2 years ago

5 0

Answer:

7 months.

Step-by-step explanation:

1250-800=450. so more than 450 has to be spent and that comes out to 7 months where you'll spend 455

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The garden shown at right is divided into two section by a fence. If the quadrilateral section is a square, what is the square a

qaws [65]

The area of the triangle is 24 ft² while the area of the square is 64 ft²

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Area of triangle = (1/2) * base * height = 0.5 * 8 * 6 = 24 ft²

Area of square = 8 ft * 8 ft = 64 ft²

The area of the triangle is 24 ft² while the area of the square is 64 ft²

Find out more on equation at: brainly.com/question/2972832

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6 0

2 years ago

Approximately how many times as large was the world population as the United States population in

stealth61 [152]

Answer: 20

Step-by-step explanation:

7 0

2 years ago

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

What is a 100 x10000

emmasim [6.3K]

1000000
Hope this helps! :)

7 0

3 years ago

Read 2 more answers

Sqrt(2x-6)=3-x<br> Solve for x

soldi70 [24.7K]

Answer:

x = 3

Step-by-step explanation:

$\sqrt{2x - 6} = 3 - x$

Square both sides of the equation

$2x - 6 = (3 - x)^{2} = 9 - 6x + x^{2} \\$

$x^{2} - 8x + 15 = 0\\$

(x - 3)(x - 5) = 0

x = 3 or 5

Now, you must always check your results because a result may not satisfy the original equation.

If x = 3, then $\sqrt{2x - 6} = \sqrt{2(3) - 6} = \sqrt{6 - 6} = \sqrt{0} = 0$ and 3 - x = 3 - 3 = 0

So 3 satisfies the original.

If x = 5, then $\sqrt{2(5) - 6} = \sqrt{10 - 6} = \sqrt{4} = 2$ , but 3 - x = 3 - 5 = -2. Therefore, 5 does NOT satisfy the original equation.

That means that x = 3 is the solution to the equation.

5 0

2 years ago