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hodyreva [135]
3 years ago
10

Equation which i dont like math not no brainly my question 3 (k-12)=k-30

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0
3 (k-12) = k-30

3k - 36 = k - 30

3k - k = -30 + 36

2k = 6

k = 3
ollegr [7]3 years ago
7 0
First you distribute and get 3k-36=k-30.
Next you bring the variables to one side and it becomes 2k-36=-30
Then you add 36 to both sides and you get 2k=6
Lastly you divide by 2 and you get k=3 which is the answer
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Find the missing lengths: LK=15 and KH=9, find KI and HI.
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Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

base^2+perpendicular^2=hypotenuse^2

Use Pythagoras in triangle HKL

LH^2+KH^2=LK^2

(LH)^2+9^2=15^2

(LH)^2+81=225

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Taking square root on both sides.

LH=12

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

(KI)^2+15^2=(12+x)^2

(KI)^2+225=x^2+24x+144

(KI)^2=x^2+24x+144-225

(KI)^2=x^2+24x-81...(1)

Use Pythagoras theorem in ΔHKI,

(KI)^2=x^2+9^2

(KI)^2=x^2+81...(2)

From (1) and (2) we get

x^2+81=x^2+24x-81

24x=162

x=\dfrac{162}{24}=6.75

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

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Taking square root on both sides.

KI=\sqrt{126.5625}

KI=11.25

Hence, the measure of KI is 11.25 units.

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3 years ago
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