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3 years ago

Equation which i dont like math not no brainly my question 3 (k-12)=k-30

Mathematics

2 answers:

vaieri [72.5K]3 years ago

7 0

3 (k-12) = k-30

3k - 36 = k - 30

3k - k = -30 + 36

2k = 6

k = 3

ollegr [7]3 years ago

7 0

First you distribute and get 3k-36=k-30.
Next you bring the variables to one side and it becomes 2k-36=-30
Then you add 36 to both sides and you get 2k=6
Lastly you divide by 2 and you get k=3 which is the answer

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2(-3/2 + 4 ÷ -11) <br> A=-43/9<br> B=-49/11<br> C=-20/11<br> D=-10/9

Vladimir [108]

Answer:

-41/11

Step-by-step explanation:

4/-11=-4/11

-3/2+(-4/11)=-3/2-4/11=-41/22

2(-41/22)=-41/11

6 0

3 years ago

in a poll 303 students voted . nominee d received 2/3 of the votes how many votes did nominee d receive

Dmitry_Shevchenko [17]

Answer:

Nominee d receive 202 votes.

Step-by-step explanation:

Given : In a poll 303 students voted. Nominee d received $\frac{2}{3}$ of the votes.

To find : How many votes did nominee d receive ?

Solution :

The number of votes = 303

Nominee d received $\frac{2}{3}$ of the votes.

i.e. $n=\frac{2}{3}\times 303$

$n=2\times 101$

$n=202$

Therefore, nominee d receive 202 votes.

5 0

3 years ago

Find the set of values of k for which the line y=kx-4 intersects the curve y=x²-2x at 2 distinct points?

Sonbull [250]

Answer:

$-6 < k < 2$

Step-by-step explanation:

Given

$y = x^2 - 2x$

$y =kx -4$

Required

Possible values of k

The general quadratic equation is:

$ax^2 + bx + c = 0$

Subtract $y = x^2 - 2x$ and $y =kx -4$

$y - y = x^2 - 2x - kx +4$

$0 = x^2 - 2x - kx +4$

Factorize:

$0 = x^2 +x(-2 - k) +4$

Rewrite as:

$x^2 +x(-2 - k) +4=0$

Compare the above equation to: $ax^2 + bx + c = 0$

$a = 1$

$b= -2-k$

$c =4$

For the equation to have two distinct solution, the following must be true:

$b^2 - 4ac > 0$

So, we have:

$(-2-k)^2 -4*1*4>0$

$(-2-k)^2 -16>0$

Expand

$4 +4k+k^2-16>0$

Rewrite as:

$k^2 + 4k - 16 + 4 >0$

$k^2 + 4k - 12 >0$

Expand

$k^2 + 6k-2k - 12 >0$

Factorize

$k(k + 6)-2(k + 6) >0$

Factor out k + 6

$(k -2)(k + 6) >0$

Split:

$k -2 > 0$ or $k + 6> 0$

So:

$k > 2$ or k $> -6$

To make the above inequality true, we set:

$k < 2$ or $k >-6$

So, the set of values of k is:

$-6 < k < 2$

3 0

3 years ago

the population density of themville is 17.5 thems per acre. Exactly 840 thems live in themville how many acress if themville

postnew [5]

I believe the answer you are looking for is 840 ÷ 17.5 which is 48 acres.

8 0

3 years ago

A luxury liner leaves a port on a bearing of 110 degrees and travels 8.8 miles. It then turns due west and travels 2.4 miles. Ho

myrzilka [38]

Answer:

Distance= 6.6 miles

Bearing= N 62.854°W

Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

Using cosine rule

Let the distance between the liner and the port be x

X² =8.8²+2.4²-2(8.8)(2.4)cos20

X²= 77.44 + 5.76-(39.69)

X²= 43.51

X= √43.51

X= 6.596

X= 6.6 miles

Let's determine the angles within the triangle using sine rule

2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

0.1244 = sin b

7.146= b°

Angle c= 180-20-7.146

Angle c= 152.854°

For the bearing

110+7.146= 117.146

180-117.146= 62.854°

Bearing= N 62.854°W

8 0

3 years ago