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3 years ago

-3(x - 6) - 3 x greater than or equal to 12

Mathematics

1 answer:

serg [7]3 years ago

4 0

Answer:

EQUAL

Step-by-step explanation:

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She has read 6 of the books from the library.

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The table represents a linear function. A two column table with six rows. The first column, x, has the entries, negative 2, nega

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M = - 4
Slope of function = - 4

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Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.

frutty [35]

<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

$2^n\leq 2^{n+1}-2^{n-1}-1$

where n is a positive integer.

Let us take n=1

then we have:

$2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2$

Hence, the result is true for n=1.

Let us assume that the result is true for n=k

i.e.

$2^k\leq 2^{k+1}-2^{k-1}-1$

Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u> $2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1$

Let us take n=k+1

Hence, we have:

$2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)$

( Since, the result was true for n=k )

Hence, we have:

$2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2$

Also, we know that:

$-2$

(

Since, for n=k+1 being a positive integer we have:

$2^{(k+1)+1}-2^{(k+1)-1}>0$ )

Hence, we have finally,

$2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1$

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

$2^n\leq 2^{n+1}-2^{n-1}-1$ where n is a positive integer.

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3 years ago

What is the function of this graph?

Lesechka [4]

Answer:

x=y^2-2

Step-by-step explanation:

This graph, is a parabola that opens to the right.

To answer this question, we just use the vertex form of a sideways parabola- x=a(y-k)^2+h.

In this case, the vertex is (-2, 0), and our value of a is 1, since it opens to the right.

This gives us: x=1(y-0)^2+(-2)

Which simplifies to: x=y^2-2.

Also, the answer to the previous two questions are wrong.

The D value (Domain) is actually [2, ∞)

The R value (Range) is actually "All real numbers" (-∞, ∞)

Let me know if this helps!

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2 years ago

Translate the word phrase into a math expression.

algol13

I believe the answer is A

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3 years ago

-3(x - 6) - 3 x greater than or equal to 12​

-3(x - 6) - 3 x greater than or equal to 12