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Alenkinab [10]
3 years ago
14

Using the following equation, find the center and radius of the circle: x^2 + y^2 +2x − 4y − 20 = 0

Mathematics
1 answer:
DanielleElmas [232]3 years ago
6 0
You have to complete the squares on both the x terms and the y terms in order to solve this. Move the 20 over to the other side so it's negative. Group the x terms together and complete the square to get (x^2+2x+1) and then do the same with the y terms: (y^2-4y+4). You have to add 1 and 4 to other side with the 20 to get a 25. Then create 2 perfect square binomials within each x and y value to get the vertex coordinates: (x+1)^2 + (y-2)^2 = 25. This tells us that the vertex is located at (-1, 2) and the radius is the square root of 25 which is 5.So the answer is the first choice above.
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Four points are graphed on the number line below.
UkoKoshka [18]

Answer:

It's close between Y and Z, but I'd go with Z

Step-by-step explanation:

-\sqrt{5}≈-2.2360679775

7 0
3 years ago
Which of these ratios are equivalent ratio<br> 1:4 2:8 3:6 7:28
Harrizon [31]

Answer:

1:4

2:8

7:28

Step-by-step explanation:

  • 1:4
  • 2:8 , 1:4
  • 7:28, 1:4
5 0
2 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
Vitek1552 [10]

Answer:

2ab - 6a + 5b - 15

Step-by-step explanation:

Given

2ab - 6a + 5b + \_

Required

Fill in the gap to produce the product of linear expressions

2ab - 6a + 5b + \_

Split to 2

(2ab - 6a) + (5b + \_)

Factorize the first bracket

2a(b - 3) + (5b + \_)

Represent the _ with X

2a(b - 3) + (5b + X)

Factorize the second bracket

2a(b - 3) + 5(b + \frac{X}{5})

To result in a linear expression, then the following condition must be satisfied;

b - 3 = b + \frac{X}{5}

Subtract b from both sides

b - b- 3 = b - b+ \frac{X}{5}

- 3 = \frac{X}{5}

Multiply both sides by 5

- 3 * 5 = \frac{X}{5} * 5

X = -15

Substitute -15 for X in 2a(b - 3) + 5(b + \frac{X}{5})

2a(b - 3) + 5(b + \frac{-15}{5})

2a(b - 3) + 5(b - \frac{15}{5})

2a(b - 3) + 5(b - 3)

(2a + 5)(b - 3)

The two linear expressions are (2a+ 5) and (b - 3)

Their product will result in 2ab - 6a + 5b - 15

<em>Hence, the constant is -15</em>

3 0
3 years ago
Draw a X over the multiples of 10. What digit do all multiples of 10 have in common?
nata0808 [166]
All multiples of 10 end in a zero besides the number zero. So 10, 20, 30 and so on....
8 0
3 years ago
Suppose f(x)=6x-2 and g(x)=2x+4). Find each of the following functions.
makvit [3.9K]

a. (f+g)(x) = 8x+2

b. (f-g)(x) = 4x-6

Step-by-step explanation:

Given

f(x) = 6x-2\\and\\g(x)=2x+4

<u>a. (f+g)(x)</u>

(f+g)(x)=f(x)+g(x)\\=6x-2+(2x+4)\\=6x-2+2x+4\\=6x+2x-2+4\\=8x+2

<u>b. (f-g)(x)</u>

(f-g)(x)=f(x)-g(x)\\=(6x-2)-(2x+4)\\=6x-2-2x-4\\=6x-2x-2-4\\=4x-6

Hence,

a. (f+g)(x) = 8x+2

b. (f-g)(x) = 4x-6

Keywords: Functions

Learn more about functions at:

  • brainly.com/question/5282516
  • brainly.com/question/5424148

#LearnwithBrainly

8 0
3 years ago
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