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kirza4 [7]
3 years ago
10

Write the statement below as a bicondtional.

Mathematics
2 answers:
gulaghasi [49]3 years ago
6 0
It's the third choice because a biconditional statement is an "if and only if " statement, using all the same words in the original statement.
Elis [28]3 years ago
3 0

Answer:

the answer is C

Step-by-step explanation:

hope this helps :)

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Marrrta [24]
It's C x5 the correct answer I'm not sure
3 0
3 years ago
Is 1.1 less than or greater than or equal to the square root of two
dangina [55]

Answer:

less than

Step-by-step explanation:

the Square root of 2 is 1.4142...

3 0
3 years ago
What is the value of 5^3¡^9
OLEGan [10]

Answer:

125i

Step-by-step explanation:

We want to find

5^3i^9

This can be rewritten as;

5^3i^8\times i

5^3(i^2)^4\times i

Recall that; i^2=-1

5^3(-1)^4\times i

We evaluate now to obtain;

125(1)\times i=125i

6 0
2 years ago
Point J is on line segment I K ‾ IK . Given J K = x + 6 , JK=x+6, I J = 9 , IJ=9, and I K = 2 x , IK=2x, determine the numerical
denpristay [2]

Answer:21

Step-by-step explanation:

4 0
3 years ago
6. If the net investment function is given by
Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated  capital for the period.

  • (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

  • (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

I(t) = 100 \cdot e^{0.1 \cdot t}

(a) The capital formation is given as follows;

\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot  e^{0.1 \cdot t}} + C

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore,  for the three years; Year 3, year 4, and year 5, we have;

\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

\displaystyle  \mathbf{\left[1000 \cdot  e^{0.1 \cdot t}} + C \right]^t_0} = 100,000

Which gives;

\displaystyle 1000 \cdot  e^{0.1 \cdot t}} - 1000 = 100,000

\displaystyle \mathbf{1000 \cdot  e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000

\displaystyle e^{0.1 \cdot t}} = 101

\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0
2 years ago
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