What is 7/3 divided by 9

Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th

dem82 [27]

Answer:

1.25$/per quart of oil. 14.05 starting fee.

Step-by-step explanation:

Give a variable that one quart of oil is o.

5o + starting fee +2.5 = 7o + starting fee

2o = 2.5

o = 1.25

substitute and we know starting fee is 14.05

8 0

4 years ago

Read 2 more answers

812,000,006 in expanded form

cestrela7 [59]

8x100,000,000+1x10,000,000+2,000,000+6x1

5 0

3 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago

Find the center and radius of the circle whose equation is <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20y%5E%7B2%7D%

LenaWriter [7]

Answer:

the center is (3,1) and the radius is √6.

Step-by-step explanation:

The center of a circle can be found using the equation $(x-h)^2 + (y-k)^2 = r^2$ and is (h,k) from it. Notice h and k are the opposite value as in the equation.

First write the equation in this form.

$x^2 - 6x + ( ?)+ y^2 - 2y + (?) + 4 = 0$

Complete the square with each variable to find what numbers should go in place of the question marks.

$(-6/2)^2 = -3^2 = 9$

$(-2/2)^2 = -1^2 = 1$

Add 1 and 9 to both sides of the equation.

$x^2 - 6x + 9 + y^2 - 2y + 1 + 4 = 1 + 9\\(x-3)^2 + (y-1)^2 + 4 = 10\\(x-3)^2 + (y-1)^2 = 6$

So the center is (3,1) and the radius is √6.

4 0

3 years ago

It’s another one thanks for the help

Paul [167]

Answer:

Step-by-step explanation:

volume of a cylinder=πr^2*h

226.2=3.14*8*r^2

226.2=25.12*r^2

226.2/25.12=r^2

9=r^2

$\sqrt{9$ =r

3=r

radius =3 feet

7 0

3 years ago