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aleksandrvk [35]
4 years ago
13

Help? Create a situation in which a conditional probability would be used. Example: What is the probability of choosing a class

president, given that the student is a female?
Mathematics
1 answer:
Masteriza [31]4 years ago
7 0
Hm. one that would come to mind is the fact that a professor is applying for a job at a highschool when they have no teaching expireince. hope this helps
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Explain how to use a number line to find a decimal equivalent to 1 7/10..
IRISSAK [1]
1 and 7 because the all what equal it selfe
3 0
3 years ago
3 over 5 + 21 over 5 =?
kicyunya [14]

4.8

Step-by-step explanation:

3 over 5+21 over 5=4.8

7 0
3 years ago
Read 2 more answers
What integer represents a five-yard law
vovangra [49]
I have never heard of a five-yard law so i have no clue but maybe a 5 yard lawn is possible
7 0
3 years ago
The following random sample from a population whose values were normally distributed was collected.10 8 11 11The 95% confidence
Margaret [11]

Answer:

Answer:

B

Step-by-step explanation:

First to find the sample mean

Xbar= summation x/n= 40/4= 10

The sample standard deviation is:

S= √summation(x-xbar)²/ n-1

=√6/3= 1.4142

The degrees of freedom

df= N-1= 4-1= 3

For 95% confidence level, critical value of t

t= 3.182

The 95% confidence interval is:

=Xbar plus or minus t' *8/√n

= 10 plus or minus 3.182(1.4142/√4)

= 10plus or minus 2.25

So 7.75 or 12.25

6 0
4 years ago
1. How many ways are there to make an octagon with 19 different sticks when order DOESN’T matter?
Oksanka [162]

Answer:

1. 75582

2. 3047466240

Step-by-step explanation:

1.  If order does not matter, this is a combination problem.  You are choosing 8 sticks from a set of 19. (Octagons have 8 sides.)

The formula for combinations of n things chosen r at a time "n choose r" is

_nC_r = \frac{n!}{r!(n-r)!}

_19C_8=\frac{19!}{8!(19-8)!} = \frac{19!}{8!11!}=75582

2. If order matters, there are more possibilities. This is a permutation problem.  The number of permutations of 19 things taken 8 at a time, "19 permute 8" is

_nP_r=\frac{n!}{(n-r)!} \\ _{19}P_8=\frac{19!}{(19-8)!} = 3047466240

6 0
3 years ago
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