3 years ago

I need help, please, I really need a help, please.

Mathematics

1 answer:

Vanyuwa [196]3 years ago

6 0

The Answer Would Be CF

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MrRissso [65]

Since y=y. set the equations equal to each then solve
2x + 1 = -x + 4
+x +x
3x + 1 = 4
-1 -1
3x = 3
/3 /3
x = 1

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3 years ago

find h and k such that the equation 3x^2 -hx +4k =0, so that the sum of the solutions is -12 and the product of the solutions is

Radda [10]

Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20

(x - a)(x - b) = 0

(x - (-2))(x - (-10)) = 0

(x + 2)(x + 10) = 0

x^2 + 10x + 2x + 20 = 0

x^2 + 12x + 20 = 0

-h = 12

h = -12

4k = 20

k = 5

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3 years ago

Juan bought 12 pounds of dog food for $15.72. What is the price per pound of the dog food?

Greeley [361]

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2 years ago

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HELP ASAP PLZ THNZS!!! ( There r 2 questions)

forsale [732]

Answer:

Step-by-step explanation:

1. Answer below

$2x = \sqrt[3]{125}$

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2. Answer below

$x + 3^{2} = \sqrt[3]{27}$

$x + 9 = 3$

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3 years ago

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