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2 years ago

Develop an explicit formula in terms of n for the nth term of the following sequence:

Mathematics

1 answer:

nalin [4]2 years ago

4 0

<h2>Answer with explanation:</h2>

The given sequence : 0,4,18,48,100,180,......

We can write the terms of the sequence as :

$\text{Ist term }:a_1=1(1^2-1)=0\\\\\text{IInd term }: a_2=2^2(2-1)=4(2-1)=4\\\\\text{IIIrd term }:a_3=3^2(3-1)=9(2)=18\\\\\text{IVth term }:a_4=4^2(4-1)=(16)(3)=48\\\\\text{Vth term }:a_5=5^2(5-1)=25(4)=100\\\\\text{VIth term }:a_6=6^2(6-1)=36(5)=180$

From the above presentation of the terms, the explicit formula in terms of n for the nth term will be :-

$a_n=n^2(n-1)$

Put n= 7 , we get

$a_7=7^2(7-1)=49(6)=294$

Therefore, the seventh term of the given sequence = 294

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Answer:

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Now we will rationalize the denominator by multiplying $\sqrt{2}$ to the top and bottom.

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Answer:

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