6.25 is the answer to the problem
Finding two geometric means between 10 and 125:
a 1 = 10, a 4 = 1250
a 4 = a 1 * q^3
1250 = 10 * q^3
q^3 = 1250 : 10
q^3 = 125
q = 5
a 2 = 10 * 5 = 50
a 3 = 10 * 5² = 10 * 25 = 250
Answer: The two geometric means are: 50 and 250, since 10, 50, 250 , 1250 forms a geometric sequence.
X=number of boys
y=number of girls.
We can suggest the following system of equations:
x+y=33
x/y=3/8
We solve this system of equations by substitution method.
x/y=3/8 ⇒x=3y/8
(3y/8)+y=33
least common multiple=8
3y+8y=33*8
11y=33*8
y=(33*8)/11
y=3*8
y=24
x+y=33
x+24=33
x=33-24
x=9
number of boys /total number of students=9/33=3/11
There are 9 boys and 24 girls in the class.
Answer: C: 9. since 3/11 of the students are boys.
