Answer:
Step-by-step explanation:
Given
Required
Determine the height at the third rebound
At first rebound;
Second rebound
Third rebound
Hence; the equation is:
Solving further;
140 is ur answer…
Im not really sure but I think this is it
Really hope this helps
Answer:
14 km
Step-by-step explanation:
<u>1) look at the information you are given:</u>
140 km total (<em>to and from work</em>)
Note that this number includes both the distance to work and the distance from work.
He works 5 days a week.
<u>2)Figure out the distance he travels within one day</u>
This means that you should take the 140 km and divide it by 5 in order to find out the amount of km he travels each day.
<h2>
140 km / 5 days = 28 km</h2>
28 km is the amount of KM he travels each DAY.
<u>3) Figure out the distance from work to home </u>
From this point, it is important to note the question is asking for <u>the distance his work is from home.</u>
Each day, he must travel 2 times: he must go to work and go from work to home, which are both the same distance.
This means that in order to get only the distance from work to home, you must divide by 2.
<h2>
28 km / 2 = 14 km</h2>
Check the picture below.
let's firstly convert the mixed fractions to improper fractions.
![\stackrel{mixed}{7\frac{1}{2}}\implies \cfrac{7\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{15}{2}} ~\hfill \stackrel{mixed}{12\frac{1}{2}}\implies \cfrac{12\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{25}{2}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cstackrel%7Bmixed%7D%7B7%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B7%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B15%7D%7B2%7D%7D%20~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B12%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B12%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B25%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\stackrel{\textit{\Large Areas}}{\stackrel{two~triangles}{2\left[ \cfrac{1}{2}\left(\cfrac{15}{2} \right)(10) \right]}~~ + ~~\stackrel{\textit{three rectangles}}{(10)(15)~~ + ~~\left( \cfrac{15}{2} \right)(15)~~ + ~~\left( \cfrac{25}{2} \right)(15)}} \\\\\\ 75~~ + ~~150~~ + ~~112.5~~ + ~~187.5\implies \boxed{525}](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Areas%7D%7D%7B%5Cstackrel%7Btwo~triangles%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%5Cleft%28%5Ccfrac%7B15%7D%7B2%7D%20%5Cright%29%2810%29%20%5Cright%5D%7D~~%20%2B%20~~%5Cstackrel%7B%5Ctextit%7Bthree%20rectangles%7D%7D%7B%2810%29%2815%29~~%20%2B%20~~%5Cleft%28%20%5Ccfrac%7B15%7D%7B2%7D%20%5Cright%29%2815%29~~%20%2B%20~~%5Cleft%28%20%5Ccfrac%7B25%7D%7B2%7D%20%5Cright%29%2815%29%7D%7D%20%5C%5C%5C%5C%5C%5C%2075~~%20%2B%20~~150~~%20%2B%20~~112.5~~%20%2B%20~~187.5%5Cimplies%20%5Cboxed%7B525%7D)
To determine the effect of changing the diameter of a sphere to its volume, we would need to know the formula for the volume of a sphere which is V = 4πr³/3 where r is half of the diameter. As you can see, there is a direct relationship.
r1 = d1/2
r2 = d2/2 = 2d1/2 = d1
V2/V1 = (4πd1³/3) / (4π(d1/2)³/3)
V2/V1 = 8
Therefore, the volume of the sphere would be 8 times the original volume.
