Hey there! :D
The biggest thing to remember here is the similar triangles and their side lengths.
Okay, so we can separate these triangles into 3 similar triangles. Which, we only need to do that to two for a proportion, but if you were to have more variables, you could separate the triangles even more if you needed to.
We want to find two triangles that have "x" has a value of their side, so we can solve a proportion.
The bigger triangle, (the whole two triangles combine) and the smaller triangle on the left can be used to make a proportion.
On the smaller triangle:
We have 9 cm on the shorter side and x as the hypotenuse.
On the larger triangle:
We have x as the shorter side, and then 25 as the hypotenuse. (9+16)
Note: You have to flip the larger triangle upside down to make it a similar structure to the other two triangles. It is similar, you just have to flip it.
So, now we can make a proportion.

Now, cross multiply.
9*25= 225
x*x=

So, find the square root.
√225= 15
x= 15. I hope this helps!
~kaikers
Answer:
16 cm.
Step-by-step explanation:
It is 4 times the ratio.
Sin (tan^(-1)X)
Sin (1/tan X)
Sin (1/1 / tan X/1)
Tan X = sin X/cos X
Sin (1/1 / sin X/cos X)
Sin (1/1 • cos X/Sin X)
Sin (cos X/sin X )
Cos X.
I believe the correct answer is cos X.
Answer:
C.
make me brainlest if you copy okay
Answer:
No
Step-by-step explanation:
Complex answer: For a point to be in quadrant II, it must have a negative x value and a positive y value.
Simple answer: The 1 would have to be negative to be in quadrant II, and it isn't