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4 years ago

Which symbol replaces ? to make the statement true?

2 answers:

5 0

4*16-16 ? 4[24-2(4+8)]
Since 16+16+16+16 is the same as 4*16 I'l just make it 3*16 (because you minus 16 from it)

3*16 ? 4[24-2(4+8)]
48 ? 4[24-2(4+8)]
48 ? 4[24-2*12]
49 ? 4(24-24)
49 ? 4*0
49 ? 0
49>0

So it is a >

Hope this helps :)

lara31 [8.8K]4 years ago

4 0

The right answer for K12 is ( > ) I Took the test and is correct. 4×16-16 > 4×[24-2×(4+8)]

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Which of the quadratic functions has the widest graph y=0.6x^2 y=4x^2 y=1/5x^2 y=1/4x^2

Tems11 [23]

Answer:

1/5x^2

Step-by-step explanation:

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3 years ago

Write the equation you would use to find x, then solve for x.

goldfiish [28.3K]

Answer:

x + 6x+10 + x+2 = 180

x = 21

Step-by-step explanation:

The sum of the angles of a triangle add to 180 degrees

x + 6x+10 + x+2 = 180

Combine like terms

8x + 12 = 180

Subtract 12 from each side

8x+12-12 = 180-12

8x =168

Divide each side by 8

8x/8 = 168/8

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6 0

3 years ago

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Robert needs to cut four shelves from a board that is 2.5 meters long. The second shelf is 18 centimeters longer than twice the

jeyben [28]

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8 0

3 years ago

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kaheart [24]

Step-by-step explanation:

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3 years ago

the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr

Naily [24]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}$

$\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k$

$\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}$

5 0

4 years ago

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