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3 years ago

Please I real really need help for this right now

Mathematics

1 answer:

kari74 [83]3 years ago

3 0

Answer:

-16/4 + 11/4

then u find common mutiples

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Write the equation in function form: 3y - 12x = 0

ivanzaharov [21]

Answer: 4x

Step-by-step explanation: Move all terms that don't contain y to the right side and solve. y = 4x

6 0

3 years ago

Read 2 more answers

X/5=2/3=5/y 2/3 4/9 1

Mademuasel [1]

$\frac{x}{5}= \frac{2}{3} = \frac{5}{y}$
Break the equation into parts;
$\frac{x}{5} = \frac{2}{3} ; \frac{2}{3}= \frac{5}{y}$
Solving for x;
$\frac{x}{5} = \frac{2}{3}$
x= $\frac{10}{3}$
Solving for y;
$\frac{2}{3} = \frac{5}{y} 
y= \frac{3*5}{2} 
y= \frac{15}{2}$
$\frac{x}{y} = \frac{10/3}{15/2}$
$\frac{x}{y} = \frac{4}{15}$

5 0

3 years ago

If you ride your bike 12 miles per hour, how long would it take you to travel 72 miles ?

poizon [28]

Answer:

It would take 6 hours for you to travel 72 miles.

Step-by-step explanation:

This question can be solved by a simple rule of three.

We have that:

Each hour, you ride 12 miles.

How many hours will take for you to travel 72 miles?

So:

1 hour - 12 miles

x hours - 72 miles

12x = 72

x = 72/12

x = 6

It would take 6 hours for you to travel 72 miles.

4 0

3 years ago

Will give brainliest! Probability

alex41 [277]

Answer:

1/49

Step-by-step explanation:

You wrote the problem correctly. You just needed to multiply instead of add.

1/7*1/7=1/49

So the answer is 1/49.

3 0

3 years ago

Read 2 more answers

Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

laila [671]

Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of years that the time could be read at night is 30.4 years.

5 0

3 years ago