All categories

3 years ago

18x^2+69x+60 Factor the expression

1 answer:

6 0

3(3x+4)(2x+5)

Because you factor out the 3 and then factor 6x^2+23x+20
That becomes (6x^2+8x)+(15x+20)
Factor out a two from the left and five from the right.
That makes 2x(3x+4) + 5(3x+4)
That becomes (3x+4)(2x+5)
Then put the three back in front.

You might be interested in

0.376×800=(0.376×_____)×100 =______×100 =______

sergey [27]

0.376*800

=(0.376*8)*100

=3.008*100

=300.8

3 0

3 years ago

Leticia charges $8 per hour to babysit. She babysat Friday night for 4 hours,

lions [1.4K]

Answer:

5 hours

Step-by-step explanation:

so you do 8 times 4

which gives you 32

72 - 32

40 divided by 8

3 0

3 years ago

Which of the following is not a promotional tactic used by a seller?

Leviafan [203]

Answer:

we conclude that the 'bait and switch' technique is not a promotional tactic used by a seller.

Hence, 'a' is the correct option.

Step-by-step explanation:

From the given options, the 'bait and switch' technique is not a promotional tactic used by a seller.

'Bait and switch' is a deceptive sale practice using which the sells try to attract (bait) the customers by offering attractive prices on certain items, but when the customers tend to go to the shop to buy the items, they witness the unavailability of the goods, or find the prices go higher compared to what they had been offered.

Now, since the customers are already present at the shop, the sellers try to pressurize the customer so that they could buy something else.

Therefore, we conclude that the 'bait and switch' technique is not a promotional tactic used by a seller.

Hence, 'a' is the correct option.

6 0

3 years ago

Read 2 more answers

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago

The Torrence family has a rectangular, in-ground pool in their yard. It holds 1700 ft of water. If it is 17 ft wide and 4 ft dee

xeze [42]

9514 1404 393

Answer:

25 ft

Step-by-step explanation:

The volume is given by the formula ...

V = LWD . . . . . the product of length, width, depth

Solving for L, we have ...

L = V/(WD) = (1700 ft³)/((17 ft)(4 ft)) = 100/4 ft = 25 ft

The length of the pool is 25 ft.

4 0

3 years ago