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4 years ago

18x^2+69x+60 Factor the expression

1 answer:

6 0

3(3x+4)(2x+5)

Because you factor out the 3 and then factor 6x^2+23x+20
That becomes (6x^2+8x)+(15x+20)
Factor out a two from the left and five from the right.
That makes 2x(3x+4) + 5(3x+4)
That becomes (3x+4)(2x+5)
Then put the three back in front.

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4 years ago

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3 years ago

What percent of workers have output more than 70 units?

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3 years ago

Read 2 more answers

The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth

Bess [88]

Answer:

Perimeter of given regular hexagon is 48.5 ft.

Step-by-step explanation:

Let ABCDEF be the regular hexagon as shown in the attached figure.

O be the intersection point of the diagonals EB, FC and AD.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

$\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE$ are equilateral $\triangle s$ .

Area of an equilateral $\triangle$ is defined as :

$\dfrac{\sqrt{3}}{4} \times a^{2}$

Where a is the side of $\triangle$ .

Area of hexagon = $6 \times \dfrac{\sqrt{3}}{4}\times a^{2}$

We are given that area of hexagon = 169.74 $ft^{2}$

Let s be the side of hexagon.

$\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft$

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = $6 \times side$

Perimeter = $6 \times 8.08$

$\Rightarrow 48.5 ft$

So, perimeter of given regular hexagon is $48.5 ft$ .

6 0

3 years ago

Needhelpslovingthisproblem

Mnenie [13.5K]

Answer:

-4 to -1.5

Step-by-step explanation:

When the graph start to slope downwards or go down its decreasing. So when the hump starts to go down at (-4,0) it then starts to go up again after (-1.5,0). Hope this helps:)

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3 years ago