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yuradex [85]
3 years ago
13

Answer in factored form x^2+11x+7

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
7 0
X² <span>+ 11x + 7

because 7 is a prime number, this doesn't factor prettily. you'll want to use the quadratic formula; if you aren't familiar with it, i'd either research it or look it up in your textbook, because it's clunky and not easily understood in this format:

(-b </span>± √((b)² - 4ac))/(2a)

in your equation x² + 11x + 7 ... a = 1, b = 11, and c = 7. what you do is you take the coefficients of every term, then plug it into your equation:
(-11 ± √((11)² - 4(1)(7))/(2(1))

not pretty, i know. but, regardless, you can simplify it:
(-11 ± √((11)² - 4(1)(7))/(2(1))
(-11 ± √(121 - 28))/2
(-11 ± √93)/2

and you can't simplify it further. -11 isn't divisible by 2, and 93 doesn't have a perfect square that you can take out from beneath the radical. the ± plus/minus symbol indicates that you have 2 answers, so you can write them out separately:

(x - (-11 - √93)/2) and (x + (-11 - √93)/2)

they look confusing, but those are your two factors. they can be simplified just slightly by changing the signs in the middle due to the -11:

(x + (11 + √93)/2) (x - (11 - √93)/2)

and how these would read, just in case the formatting is too confusing for you: x plus the fraction 11 + root 93 divided by 2. the 11s and root 93s are your numerator, 2s are your denominator.
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The diameter of Circle Q terminates on the circumference of the circle at (3,0) and (3,-7) . Write the equation of the circle in
Deffense [45]

Step-by-step explanation:

The center of a circle with 2 end points of a di diameter is the midpoint of the two endpoints.

The formula needed to find the minpoints is

(x,y) = (x2 + x1)/2, (y2 + y1)/2

x2 = 3

x1 = 3

y2 = 0

y1 = -7

midpoint = (3 + 3)/2, (0 - 7)/2

midp[oint = 3,-3.5

The midpoint is the center of the circle. Observe that the signs get changed when entering the values for (x,y)

So far what you have is (x - 3)^2 + (y + 3.5)^2 = r^2

To determine r^2 you need only take the distance from the center to oneof the endpoints.

r^2 = (3 - 3)^2 + (3.5 - 0)^2

r^2 = 3.5^2

r^2 = 12.25

Answer: (x - 3)^2 + (y + 3.5)^2 = 12.25

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I need help with number 1-4 I don’t understand..
Karo-lina-s [1.5K]

Answer:

  1. 109°, obtuse
  2. 131°, obtuse
  3. 53°, acute
  4. 124°, obtuse

Step-by-step explanation:

You are exected to know the relationships of angles created where a transversal crosses parallel lines.

  • Corresponding angles are equal (congruent).
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The appearance of the diagram often gives you a clue.

You also expected to know the name (or category) of angles less than, equal to, or greater than 90°. Respectively, these are <em>acute</em>, <em>right</em>, and <em>obtuse</em> angles.

1. Adjacent angles are supplementary. The supplement of the given angle is 109°, so x will be obtuse.

2. Opposite exterior angles are equal, so y will be 131°. It is obtuse.

3. Opposite interior angles are equal, so w will be 53°. It is acute.

4. Corresponding angles are equal, so x will be 124°. It is obtuse.

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