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Mariulka [41]
3 years ago
14

Help me. And fasttttttttt.

Mathematics
1 answer:
ivann1987 [24]3 years ago
5 0

Answer:

\sqrt{85} = 9.2195 = 9.22

\sqrt{17} = 4.123

Step-by-step explanation:

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Am I correct? If not what did I do wrong
LUCKY_DIMON [66]

    You are not correct. Here's an explanation as to why: First of all, the triangle is isosceles, since it has two congruent sides that leads to the conclusion of two congruent angles, one opposite each side. This means that all three angle measurements of the triangle are x degrees, x degrees, and 40 degrees. To solve for x, add all three values together and set them equal to 180 degrees, the sum of three angles in any triangle. Your mistake is adding only one x to 40, which isn't inclusive of all three triangles. I hope this helped!

5 0
3 years ago
An ion channel can be in either open (O) or closed (C) states. If it is open, then it has probability 0.1 of closing in 1 micros
iragen [17]

Answer:

a)  P (COO)  = 0,135

b) P ( SISI) = 0,00015

Step-by-step explanation:

a) the probability of an ion channel in open position is 50 %   0,5

   the probability of an ion channel in close position is 50 %   0,5

probability for the following sequence of states COO

to be closed   0,5    (C)

from (C) to pass to open  0,3  (O)

and to stay O  is 0,9

Then the probability of the sequence of states COO is

P (COO)  = 0,5 * 0,3 * 0,9  

P (COO)  = 0,135

b) If people are either infected or susceptible, then

Probability of an individual infected is  0,5

Probability of an individual susceptible  is 0,5

to pass from susceptible to infected is 0,05

to pass from infected to susceptible is 0,12

then

P ( SISI) = 0,5 * 0,05*0,12*0,05

P ( SISI) = 0,00015

probability for the following sequence of states COO

4 0
3 years ago
A rectangular room room with a length of 16 feet, a width of 14 feet, and a height of 10 feet. What is the volume of the room
patriot [66]
V=LWH (multiply the length, width and height)
So plug in the numbers,  V=6x14x10=840 ft^3 (feet cube)
7 0
3 years ago
On a baseball
vampirchik [111]

Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.

<h3>How far did the outfielder throw the ball?</h3>

Based on the shape of a mound, the law of cosines can be used.

The distance the ball was thrown by the outfielder can therefore be d.

Distance is:

d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))

d ²= 33,484.42ft

Then find the square root:

d = √33,484.42

= 182.9874

= 183 ft

Find out more solving for distance at brainly.com/question/10739348

#SPJ1

4 0
1 year ago
A sequence has three terms.
Lunna [17]

Answer: don't know sorry

Step-by-step explanation: YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET !!!!!!!!!!!!!!!!!!!!!!!!

Have a nice day Bye! :)

8 0
3 years ago
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