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seraphim [82]
3 years ago
12

Line segment AB is one unit long. If point C cuts AB so that AC = 0.618, what is the ratio of AC to CB? a. 1 c. 1.32 b. 1.618 d.

1.543  
Mathematics
1 answer:
Alecsey [184]3 years ago
7 0
By the segment addition postulate,
AB = AC+CB
since C is somewhere between A and B

We know AC is 0.618 and AB = 1
CB = x for now

AB = AC+CB
1 = 0.618+x
1-0.618 = 0.618+x-0.618 ... subtract 0.618 from both sides
0.382 = x
x = 0.382

So CB is 0.382 units long

To find the ratio of AC to CB, divide the values
AC/CB = 0.618/0.382 = 1.618 (approximate to 3 decimal places)

Answer: Choice B) 1.618
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What is the solution to x=square root 2x+3?
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4 0
3 years ago
6(1 + 3R) = 2(10R - 9) -4R
Damm [24]

Answer:

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6+18R=2(10R-9)-4R

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6+18R=20R-18-4R

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Move the variable to the left-hand side and change its sign

6+18R-16R=-18

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18R-16R=-18-6

Collect like terms

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5 0
3 years ago
Please help me- thank you
san4es73 [151]
Answer:
(2^2)(z^7)

Explanation:
The quotient rule states that if two powers have the same base and are on opposite places of a fraction (one is on the numerator, the other on the denominator), you subtract the exponents.

First looking at the powers with the bases of 2, 2^8 is the numerator and 2^6 is the denominator. When we subtract 8-6 we get 2, so 2^8/2^6 would simplify to 2^2.

Then, we look at the powers with the base of z. z^10 is the numerator and z^3 is the denominator. When we subtract 10-3 we get 7, so z^10/z^3 would simplify to z^7.

I hope this helps! Please comment if you have any questions:)
6 0
3 years ago
Read 2 more answers
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