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marusya05 [52]
3 years ago
9

What's the position of nine in the number 932,805

Mathematics
2 answers:
zmey [24]3 years ago
8 0
It is in the Hundred thousands
zheka24 [161]3 years ago
5 0
It would be in the
Hundred thousands
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Can y’all put this from greatest to least? <br> -0.3<br> 3<br> -0.9<br> 2.91<br> -1.01
sukhopar [10]

3, 2.91, -0.3, -0.9, -1.01,

6 0
3 years ago
For f(x)=13^x,find f(3/2)
tekilochka [14]

Answer:

  f(3/2) = 13√13 ≈ 46.872167

Step-by-step explanation:

Put 3/2 where x is and evaluate.

  f(3/2) = 13^(3/2) = 13^(1 +1/2) = 13√13

  f(3/2) ≈ 46.872167

5 0
3 years ago
What is the ratio for sine
Sphinxa [80]

Answer:

Blank 1: opposite

Blank 2: adjacent

Blank 3: opposite

Blank 4: adjacent

Step-by-step explanation:

There is a trigonometric acronym for this which is:

Soh Cah Toa

Soh means that sine is opposite over hypotenuse.

Cah means that cosine is adjacent over hypotenuse.

Toa means that tangent is opposite over adjacent.

Let me actually write these out as fractions:

sine is \frac{\text{opposite}}{\text{hypotenuse}}

cosine is \frac{\text{adjacent}}{\text{hypotenuse}}

tangent is \frac{\text{opposite}}{\text{adjacent}}

Blank 1: opposite

Blank 2: adjacent

Blank 3: opposite

Blank 4: adjacent

4 0
3 years ago
210 students were asked whether they want to go to a water park or a roller skating rink for a class party.
Brrunno [24]

Answer:

60.3

Step-by-step explanation:

hope this helps

4 0
3 years ago
Simplify this equation <br> Thanks a lot!!!
den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

\bf\implies a^m \times b^m = (ab)^m

Using this property , we have ,

\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}

This can be written as ,

\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}

Simplifying using ( a+b)(a-b) = a² - b² ,

\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}

Subtracting the numbers inside the brackets ,

\rm\implies (-1)^{2n - 1 }

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

\rm\implies\boxed{\quad \red{ -1 }\quad }

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>.</u>

4 0
3 years ago
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