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3 years ago

What is the greatest negative integer?

Mathematics

2 answers:

andreev551 [17]3 years ago

5 0

-1 is the greatest negative integer because the bigger the negative number the smaller it is

VMariaS [17]3 years ago

5 0

The greatest negative integer would be the one that is the closet to zero. -1 is the closest to zero.

Answer: -1

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Who made math? Explain??

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Answer:

Beginning in the 6th century BC with the Pythagoreans, with Greek mathematics the Ancient Greeks began a systematic study of mathematics as a subject in its own right. Around 300 BC, Euclid introduced the axiomatic method still used in mathematics today, consisting of definition, axiom, theorem, and proof

Step-by-step explanation:

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3 years ago

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NEED HELP

Zina [86]

Answer:

$\displaystyle \frac{1}{2}(x^3-2x^2-5x+6)$

Step-by-step explanation:

<u>Polynomials </u>

The polynomial whose graph is shown is of third degree because it has three real roots. The roots of a polynomial are the values of x that make the expression equal to zero. We can see it happens three times in the graph provided. The roots or zeros are

x=-2, x=1, x=3

The factored form of a polynomial whose roots $x_1, x_2, x_3$ are known is

$a(x-x_1)(x-x_2)(x-x_3)$

We know the value of the roots, thus the polynomial is written as

$a(x+2)(x-1)(x-3)$

We need to find the value of a. We do that by replacing the value of x=0 and finding a that makes f(0)=3 (as seen in the graph). Thus

$a(0+2)(0-1)(0-3)=3$

$a(2)(-1)(-3)=3$

$a(6)=3$

$\displaystyle a=\frac{3}{6}$

$\displaystyle a=\frac{1}{2}$

Thus the factored form of the polynomial is

$\displaystyle \frac{1}{2}(x+2)(x-1)(x-3)$

Let's multiply all the factors

$\displaystyle \frac{1}{2}(x+2)(x-1)(x-3)$

$\displaystyle \frac{1}{2}(x^2+2x-x-2)(x-3)$

$\displaystyle \frac{1}{2}(x^2+x-2)(x-3)$

$\displaystyle \frac{1}{2}(x^3-3x^2+x^2-3x-2x+6)$

$\boxed{ \displaystyle \frac{1}{2}(x^3-2x^2-5x+6)}$

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4 years ago

Sombody plees help mee. :|)))

aniked [119]

Answer:

132 i think

Step-by-step explanation:

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2 years ago

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Quadratic Equations<br> How to find x and y-intercepts from vertex form (not standard).

12345 [234]

Here is how to find the intercepts, if the graph is hovering above the x axis (k<0) there will be no real solutions for the x intercept

4 0

2 years ago

The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is approximately normally distributed with mean 1252

stich3 [128]

Answer:

a) P ( 1100 < X < 1400 ) = 0.755

b) P ( X < 1000 ) = 0.755

c) proportion ( X > 1200 ) = 65.66%

d) 5.87% percentile

Step-by-step explanation:

Solution:-

- Denote a random variable X: The number of chocolate chip in an 18-ounce bag of chocolate chip cookies.

- The RV is normally distributed with the parameters mean ( u ) and standard deviation ( s ) given:

u = 1252

s = 129

- The RV ( X ) follows normal distribution:

X ~ Norm ( 1252 , 129^2 )

a) what is the probability that a randomly selected bag contains between 1100 and 1400 chocolate chips?

- Compute the standard normal values for the limits of required probability using the following pmf for standard normal:

P ( x1 < X < x2 ) = P ( [ x1 - u ] / s < Z < [ x2 - u ] / s )

- Taking the limits x1 = 1100 and x2 = 1400. The standard normal values are:

P ( 1100 < X < 1400 ) = P ( [ 1100 - 1252 ] / 129 < Z < [ 1400 - 1252 ] / 129 )

= P ( - 1.1783 < Z < 1.14728 )

- Use the standard normal tables to determine the required probability defined by the standard values:

P ( -1.1783 < Z < 1.14728 ) = 0.755

Hence,

P ( 1100 < X < 1400 ) = 0.755 ... Answer

b) what is the probability that a randomly selected bag contains fewer than 1000 chocolate chips?

- Compute the standard normal values for the limits of required probability using the following pmf for standard normal:

P ( X < x2 ) = P ( Z < [ x2 - u ] / s )

- Taking the limit x2 = 1000. The standard normal values are:

P ( X < 1000 ) = P ( Z < [ 1000 - 1252 ] / 129 )

= P ( Z < -1.9535 )

- Use the standard normal tables to determine the required probability defined by the standard values:

P ( Z < -1.9535 ) = 0.0254

Hence,

P ( X < 1000 ) = 0.755 ... Answer

(c) what proportion of bags contains more than 1200 chocolate chips?

- Compute the standard normal values for the limits of required probability using the following pmf for standard normal:

P ( X > x1 ) = P ( Z > [ x1 - u ] / s )

- Taking the limit x1 = 1200. The standard normal values are:

P ( X > 1200 ) = P ( Z > [ 1200 - 1252 ] / 129 )

= P ( Z > 0.4031 )

- Use the standard normal tables to determine the required probability defined by the standard values:

P ( Z > 0.4031 ) = 0.6566

Hence,

proportion of X > 1200 = P ( X > 1200 )*100 = 65.66% ... Answer

d) what is the percentile rank of a bag that contains 1050 chocolate chips?

- The percentile rank is defined by the proportion of chocolate less than the desired value.

- Compute the standard normal values for the limits of required probability using the following pmf for standard normal:

P ( X < x2 ) = P ( Z < [ x2 - u ] / s )

- Taking the limit x2 = 1050. The standard normal values are:

P ( X < 1050 ) = P ( Z < [ 1050 - 1252 ] / 129 )

= P ( Z < 1.5659 )

- Use the standard normal tables to determine the required probability defined by the standard values:

P ( Z < 1.5659 ) = 0.0587

Hence,

Rank = proportion of X < 1050 = P ( X < 1050 )*100

= 0.0587*100 %

= 5.87 % ... Answer

6 0

3 years ago