this is the answer and where the parentheses -8+(3-2)+7=-16
First year: the depreciation is (35/100) x 20000 = £7000; now the value of the car is £20000 - £7000 = £13000;
Second year: the depreciation is (35/100) x 13000 = £4550; the current value of the car is £13000 - £4550 = £8450.
Answer:
-3 ≤y≤6
Step-by-step explanation:
The range is the output values or the y values
The y values go from -3 to 6 including these values
-3 ≤y≤6
Answer:
16
Step-by-step explanation:
<u>Remember that 
</u>
(-2i)(8i)
16
Answer:
3(5x−11)
Step-by-step explanation:
32+15x−42
15x−33
=3(5x−11)
