All categories

3 years ago

Convert 76000 ml into L. Please show your work.

1 answer:

5 0

To convert from one unit to another unit, a conversion factor is needed. For this case we are asked to convert from mL to L. In a conversion table, we know that 1 L is equal to 1000 mL. We use these values. We do as follows:

76000 mL ( 1 L / 1000 mL ) = 76 L

You might be interested in

Approximately _____ percent of the population are diagnosed with panic disorder using DSM criteria.

torisob [31]

DSM stands for Diagnostic and Statistical Manual of Mental Disorders. DSM is aclassification system for the mental disorders and indicates how the disorder can be distinguished from other. The DSM-5 recognized anxiety disorders are: generalized anxiety disorder, phobic disorder, panic disorder and obsessive compulsive disorder. <span>Approximately 3 percent of the population are diagnosed with panic disorder using DSM criteria.</span>

3 0

3 years ago

What is the surface area of this wedge.?

alexandr1967 [171]

Answer:

the surface area of the wedge is 360ft²

Step-by-step explanation:

6x5x3x4 = 360ft²

5 0

2 years ago

PLZ HELP QUICK I NEED TO TURN THIS IN ;Twice a number is fourteen. Write and solve an equation to nd the number of miles that mu

LuckyWell [14K]

2n=14 n being the “number” divide 2 on both sides and you’re left w n=14/2 or7

5 0

3 years ago

The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$

Therefore, the largest angle of the field is 149⁰.

8 0

3 years ago

(5.2×10−2)×(8.0×10−4)=

Digiron [165]

3800. go to math papa.

4 0

3 years ago

Read 2 more answers