4 years ago

Identify the asymptote(s) of this function: y=5/(x-4)+1

1 answer:

6 0

$y= \frac{5}{(x-4)+1}$
$y= \frac{5}{x-3}$
So you take the denominator and compare to zero.
$x-4+1=0$
$x-3=0$
$x=3$
Then the horizontal asymptote is y = 0

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