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Otrada [13]
3 years ago
14

Identify the asymptote(s) of this function: y=5/(x-4)+1

Mathematics
1 answer:
Dimas [21]3 years ago
6 0
y= \frac{5}{(x-4)+1}
y= \frac{5}{x-3}
So you take the denominator and compare to zero. 
x-4+1=0
x-3=0
x=3
Then the horizontal asymptote is y = 0
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