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KiRa [710]
4 years ago
15

HELPPPPPPPPPP and explain

Mathematics
1 answer:
mina [271]4 years ago
4 0
There is so much controversy about this question on the internet (well not this question exactly but the idea of taking a reciprocal of a discontinuous function). 

Some say you can if you make it clear that the point causing the trouble is excluded in some way. Others say that you cannot contemplate the idea. You are creating a meaningless situation with no definition. It really depends on what you have been told about division by 0. There are ways of getting around this, but you are not taking a calculus course and therefore you likely don't have the tools to deal with it. In any event, it does not look to me like you know about limits yet.  

Your marker or teacher or tutor can go either way on this problem and be justified in marking you wrong no matter what you do. As instructed I will put what I think should be done in the comment section. And remember, I'm counting noses and going with the majority when I answer this. It's not anything I'm 100% certain of, but neither is anyone else.
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A $60 sweater is on sale for 25% off. What is the sale price of the sweater?​
Damm [24]

Answer:

$45

Step-by-step explanation:

60/4=15 15x3(75%)=45

8 0
3 years ago
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Translate this phrase into an algebraic expression.
labwork [276]

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Step-by-step explanation:

4 0
3 years ago
Determine algebraically whether the function is even, odd, or neither even nor odd. (2 points)
ahrayia [7]

Answer:

f(x) is neither odd nor even function

Step-by-step explanation:

we are given

f(x)=-3x^4-2x-5

Firstly, we will find f(-x)

we can replace x as -x

we get

f(-x)=-3(-x)^4-2(-x)-5

now, we can simplify it

f(-x)=-3x^4+2x-5

we can see that

it is neither equal to f(x) nor -f(x)

we know that

For even:

f(-x)=f(x)

For odd:

f(-x)=-f(x)

so, f(x) is neither odd nor even function

3 0
3 years ago
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Solve the equation x^2-4x-9=29
PtichkaEL [24]

Answer:

x² - 4x - 9 = 29

x² - 4x - 9 - 29 = 0

x² - 4x - 38 = 0

Using the quadratic formula

x =  \frac{ - b± \sqrt{ {b}^{2} - 4ac }  }{2a}

Where

a = 1 , b = -4 c = - 38

So we have

x =  \frac{ -  - 4± \sqrt{ { - 4}^{2}  - 4(1)( - 38)} }{2(1)}  \\  \\ x =  \frac{4± \sqrt{16 +152 } }{2}  \\  \\ x =  \frac{4± \sqrt{168} }{ 2}  \\  \\ x =2 ± \sqrt{42}  \\  \\  \\ x = 2 +  \sqrt{42}  \:  \:  \: or \:  \:  \: x = 2 -  \sqrt{42}

Hope this helps you

4 0
3 years ago
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