Answer:
0.395 kilometre
Step-by-step explanation:
Given:
On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.
On his second stroke, the ball traveled 79 meters and went into the hole.
<u>Question asked:</u>
How many kilometres from the hole was Martin when he started?
<u>Solution:</u>
Let distance from Martin starting point to the hole in meters = 
On Martin's first stroke, ball traveled = 

On his second stroke, the ball traveled and went to the hole = 79 meters
Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke

Now, convert it into kilometre:
1000 meter = 1 km
1 meter = 
395 meters = 
Thus, there are 0.395 kilometre distance from Martin starting point to the hole.
Answer:
Step-by-step explanation:
We observe that the difference of terms is 4, 7 and 15 and next level difference is 4. It means the sequence is quadratic.
<u>We can compare this with simple quadratic sequence </u>
<u>and find out that doubling each term gives us </u>
This is close to our sequence, write the terms as follows to find exact rule
<u>The first term: </u>
- a₁ = 4 = 2*1² + 2 = 2*1² + 1 + 1
<u>The second term</u>
- a₂ = 11 = 2*2² + 3 = 2*2² + 2 + 1
<u>The third term:</u>
- a₃ = 22 = 2*3² + 4 = 2*3² + 3 + 1
<u>The fourth term:</u>
- a₄ = 37 = 2*4² + 5 = 2*4² + 4 + 1
<u>The nth term as per observation above is:</u>
Answer:
(a)Revenue function,
Marginal Revenue function, R'(x)=580-2x
(b)Fixed cost =900
.
Marginal Cost Function=300+50x
(c)Profit,
(d)x=4
Step-by-step explanation:
<u>Part A
</u>
Price Function
The revenue function

The marginal revenue function

<u>Part B
</u>
<u>(Fixed Cost)</u>
The total cost function of the company is given by 
We expand the expression

Therefore, the fixed cost is 900
.
<u>
Marginal Cost Function</u>
If 
Marginal Cost Function, 
<u>Part C
</u>
<u>Profit Function
</u>
Profit=Revenue -Total cost

<u>
Part D
</u>
To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

The number of cakes that maximizes profit is 4.
Answer:
We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.
This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>
Explanation:
In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.
So we want to find a and b such that 5, a, b, 135 is a geometric sequence.
If the common ratio is r then:
<span><span>a=5r</span><span>b=ar=5<span>r2</span></span><span>135=br=5<span>r3</span></span></span>
Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>
Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>
.53= 53/100
53/100 cannot be simplified so the answer is 53/100