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2 years ago

What is -0.38,-3/8,-0.04 in order from least to greatest

Mathematics

1 answer:

ratelena [41]2 years ago

5 0

-0.04, -3/8, -0.38 is the answer

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Please I need help with this Question

frutty [35]

Answer:

The data set with the greater range is the Girls

The greater median is the Girls at 110

Step-by-step explanation:

The range is the difference between the largest and smallest values.

As the largest value for the boys is 120 and the smallest is 60, the range would be 60

As the largest value for the girls is 150 and the smallest is 70, the range would be 80.

This means that the Girls have the greater range

The median is the number in the middle when the data is in ascending order.

As we have an even number, we will have to find the middle value between 5 and 6. To do this, we can add them together and divide them by 2.

The 5th boy in ascending order is 90 and the 6th boy is 90.

$(90+90)/2=90$

The 5th 5irl is 100 and the 6th girl is 120

$(100+120)/2=110$

This means that the median is greater for the Girls.

4 0

2 years ago

if i picked 24 flowers. Put each group of 10 flowers into a vase. How many would be leftover to give to the teacher?

Amiraneli [1.4K]

4 flowers are left over

7 0

2 years ago

Which simplified fraction is equal to 0.53 with the three repeating?

topjm [15]

Answer:

24/46 = 0.52173913

8/15 = 0.53333333

42/90 = 0.46666666

5/9 = 0.55555555

answer is 8/15

8 0

3 years ago

denis23 [38]

Answer:

C. 5units

Step-by-step explanation:

7 0

2 years ago

Write 3x^2-18x-6 in vertex form

Vedmedyk [2.9K]

The standard form of a quadratic equation is $\displaystyle{ y=ax^2+bx+c$ , while the vertex form is:

$y=a(x-h)^2+k$ , where (h, k) is the vertex of the parabola.

What we want is to write $\displaystyle{ y=3x^2-18x-6$ as $y=a(x-h)^2+k$

First, we note that all the three terms have a factor of 3, so we factorize it and write:

$\displaystyle{ y=3(x^2-6x-2)$ .

Second, we notice that $x^2-6x$ are the terms produced by $(x-3)^2=x^2-6x+9$ , without the 9. So we can write:

$x^2-6x=(x-3)^2-9$ , and substituting in $\displaystyle{ y=3(x^2-6x-2)$ we have:

$\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]$ .

Finally, distributing 3 over the two terms in the brackets we have:

$y=3[x-3]^2-33$ .

Answer: $y=3(x-3)^2-33$

6 0

3 years ago