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tankabanditka [31]
3 years ago
13

Cho is driving a car. He gets to his destination, which is 72 miles away, in 1 hour and 30 minutes. a. The equation d = rt can b

e used to model Cho’s drive, where d is the distance traveled, r is the speed of the car, and t is the amount of time spent traveling. Substitute Cho’s time and distance into the equation.
Mathematics
1 answer:
Kay [80]3 years ago
4 0

Answer:

50 miles per hour

Step-by-step explanation:

In this question, we are asked to substitute the information given into the equation. First we need consistency on units. Hence the 1hr 30 minutes is same as 1.5hrs

Now since d =rt

We need to get r = d/t

This means r = 75/1.5 = 50 miles per hour

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Rate of change of y=2x=3
Rama09 [41]

bearing in mind that the slope goes by several names

average rate of change

rate of change

rise over run

deltaY over deltaX

however, is the same cat disguised with a different costume.

\bf y=\stackrel{\stackrel{m}{\downarrow }}{2}x-3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

7 0
3 years ago
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
Convert 0.00049 to scientific notation.
SOVA2 [1]
It's 10 - 4

moving decimal over to the right makes a negative exponent.
7 0
3 years ago
Read 2 more answers
A 15 foot ladder is placed on the top of a wall. The distance from the bottom of the wall to the bottom of the ladder is 7 feet.
kati45 [8]

The height of the wall from the question is 13.27ft

<h3 /><h3>Pythagoras theorem </h3>

The theorem states that the square of the longest side is equal to the sum of square of other two sides.

From the given question

Hypotenuse (ladder length) = 15ft

Adjacent = 7feet

Required

Height of the wall H

According to the theorem

15² = 7² + H²

H² = 225 - 49

H² = 176

H = 13.27feet

Hence the height of the wall from the question is 13.27ft

Learn more on pythagoras theorem here; brainly.com/question/343682

#SPJ1

5 0
2 years ago
Please help me answer these questions asap!!
vekshin1
D= y-y1=m(x-x1)
C
B
A
8 0
3 years ago
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