I might be wrong but I think the answer would be -x+2x+6 as a simplified version because if you use the equation (x+4•x+3)-3x(x+1)=a (or any letter you choose), you will get 3x+x^2+12+4x-3x-3x^2=y. Then, you can combine like terms:
4x-2x+12=a
Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Do 35 times 19 and that is the whole square inches or so 35 squared times 19 squared
Answer:
Step-by-step explanation:
we have f=-6.5
-2.75- (-6.5)= -2.75+6.5=3.75
Area of the circle can be calculated using the following rule:
area = pi*(radius)^2
For the first circle:
We are given that:
area = 1040.9 square units ....> I
For the second circle:
We are given that:
radius = 27 units
Therefore:
area = pi * (27)^2 = 2290.221044 square units ....> II
For the third circle:
We are given that:
circumference = 87.92 units
Therefore:
circumference = 2*pi*radius = 87.92
radius = 13.99 units
area = pi*(13.99)^2 = 615.12799 square units ...> III
For the fourth circle:
We are given that:
diameter = 19 units
Therefore:
radius = 19/2 = 9.5 units
area = pi*(9.5)^2 = 283.528 square units ....> IV
Based on the above, the order according to increasing area would be:
IV , III , I , II
hope this helps :)
