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2 years ago

A dot plot is a graph that displays data by using dots plotted above a number line.

Mathematics

1 answer:

Vikentia [17]2 years ago

8 0

True, because dot plots usually look like this

0 0

0 0 0 0 0

__________________________________

1 2 3 4 5

As you can see, the dots are above the line.

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The value of x is ____ degrees, and the value of y is___degrees

solmaris [256]

Answer:

x = 112°, y = 68°

Step-by-step explanation:

68° and y are corresponding angles and are congruent, then

y = 68°

x and y are adjacent angles and are corresponding ( sum to 180° ), then

x + y = 180°

x + 68° = 180° ( subtract 68° from both sides )

x = 112°

8 0

3 years ago

Read 2 more answers

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lord [1]

Answer:

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2 years ago

Shandra's parents put $1,500 in her bank account for college tuition. Given an interest

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

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3 years ago

How many solutions will there be to the following equation? 16 x squared = 100 a. more than 2 solutions b. no solution c. 1 solu

blagie [28]

Answer:

The answer is B. No solution

Step-by-step explanation:

16x^2 is not equal to 100, so the equation is false, and there is no solution for x.

4 0

2 years ago

Which of the following shows that EFGH is a parallelogram for y=7 and z=9?

Anna35 [415]

Option B: $m \angle F=m \angle G=120^{\circ}$ and $m \angle E=60^{\circ}$ , so $\angle E$ is supplementary to both $\angle F$ and $\angle G$ , so EFGH is a parallelogram.

Option C: $m \angle F=m \angle G=120^{\circ}$ so EFGH is a parallelogram.

Option D: $m \angle E+m \angle G=180^{\circ}$ so EFGH is a parallelogram.

Explanation:

Option A: $m \angle E=m \angle F=60^{\circ}$ and $m \angle G=120^{\circ}$ so $\angle G$ is supplementary to both $\angle E$ and $\angle F$ , so EFGH is a parallelogram

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Substituting, we get, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Thus, $m \angle E\neq m \angle F$ because the measures of these angles are not equal.

Hence, Option A is not the correct answer.

Option B: $m \angle F=m \angle G=120^{\circ}$ and $m \angle E=60^{\circ}$ , so $\angle E$ is supplementary to both $\angle F$ and $\angle G$ , so EFGH is a parallelogram.

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Thus, substituting, we have, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Hence, Option B is the correct answer.

Option C: $m \angle F=m \angle G=120^{\circ}$ so EFGH is a parallelogram.

To determine the angles, let us substitute $z=9$ in $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$

Thus, $m \angle F=m \angle G=120^{\circ}$

Since, the opposite angles of a parallelogram are equal, EFGH is a parallelogram.

Hence, Option C is the correct answer.

Option D: $m \angle E+m \angle G=180^{\circ}$ so EFGH is a parallelogram.

Let us substitute $y=7$ and $z=9$ in $m \angle E=(7y+11)^{\circ}$ , $m \angle F=(17y+1)^{\circ}$ and $m \angle G=(14z-6)^{\circ}$ to determine the exact measures the angles of the parallelogram.

Substituting, we have, $m \angle E=60^{\circ}$ , $m \angle F=m \angle G=120^{\circ}$

Adding the angles E and G, we have,

$m \angle E+m \angle G=60^{\circ}+120^{\circ}=180^{\circ}$

By the property of parallelogram, any two adjacent angles add upto 180.

Thus, the adjacent angles E and G add upto 180.

Hence, Option D is the correct answer.

3 0

3 years ago