Very confused on this question, whats the answer and why
1 answer:
You just put the fractions where they say they are supposed to be, so put 7/4 in for y and put 7/6 in for x. Then, you have to first do the exponent since it comes first in PEMDAS, so after that you solve the exponent, you get -343/-216. Next, you have to do 7/4- 343/-216. After that you get the fraction 35/216.
You might be interested in
The maximum height of the rocket is 43.89 feet
<h3>How to write the function</h3>The general function is given as:
h(t) = -16t^2 + vt + h
The initial velocity is
v = 53
So, we have:
h(t) = -16t^2 + 53t + h
The initial height is
h = 0
So, we have:
h(t) = -16t^2 + 53t
Hence, the function of the height is h(t) = -16t^2 + 53t
<h3>The maximum height of the rocket</h3>
In (a), we have:
h(t) = -16t^2 + 53t
Differentiate the function
h'(t) = -32t + 53
Set to 0
-32t + 53 = 0
This gives
-32t = -53
Divide by -32
t = 1.65625
Substitute t = 1.65625 in h(t) = -16t^2 + 53t
h(1.65625) = -16 * 1.65625^2 + 53 * 1.65625
Evaluate
h(1.65625) = 43.890625
Approximate
h(1.65625) = 43.89
Hence, the maximum height of the rocket is 43.89 feet
<h3>Time to hit the ground</h3>In (a), we have
h(t) = -16t^2 + 53t
Set to 0
-16t^2 + 53t = 0
Divide through by -t
16t - 53 = 0
Add 53 to both sides
16t = 53
Divide by 16
t = 3.3125
Hence, the time to hit the ground is 3.3125 seconds
<h3>The graph of the function h(t)</h3>See attachment for the graph of the function h(t)
Read more about height functions at:
#SPJ1
