3 years ago

Given P(1,3) and Q(3,7) what is the slope of PQ

Mathematics

1 answer:

Aleksandr [31]3 years ago

8 0

Answer:

hi! you have 2 points! this means slope formula! y2-y1/x2-x1

okay all you do now is plugin! (x1 1,y1 3) (x2 3,y2 7) what I did was label your x1 y1 x2 y2! now just follow the formula and that / is division or basically a fraction

7-3/3-1

that equals -5! and that's your slope! memorize the formula it helpss!

You might be interested in

4. Evan took an exam that had 50 questions. He got 38 of the questions correct. What percentage did he

Natasha2012 [34]

Answer:76%

Step-by-step explanation:38 out of 50 equals 76%

5 0

2 years ago

Mason bought a tablecloth that measured 8 feet by 4 feet.

Y_Kistochka [10]

32feet because 8×4=32

7 0

3 years ago

Read 2 more answers

Four minus x , multiplied by 15

earnstyle [38]

It would be 4-15x
sorry if not

3 0

3 years ago

Which expression is equivalent to StartFraction 4 a + 4 Over 2 a EndFraction times StartFraction a squared Over a + 1 EndFractio

Cloud [144]

Answer:

Its 2a or C on EDGE 2020

Step-by-step explanation:

Took the test

8 0

3 years ago

Read 2 more answers

Martha has widow's peak and attached earlobes. Martha's dad had a straight hairline and unattached earlobes. If Martha marries a

krok68 [10]

Answer:

the probability of having a widow peak and attached earlobe = 0.6667*0.66667 = 0.4445 = 44.5%

Step-by-step explanation:

Martha = widow's peak + attached earlobes.

Martha's dad = straight hairline + unattached earlobes.

Martha husband =straight hairline+ widow's peak + attached earlobes

what is the probability that Martha child will have a widow's peak + attached earlobes?

since,

Martha + Martha husband =straight hairline+ widow's peak + attached earlobes

the probability of the child having widow peak is 2/3 = 0.6667

the probability of the child having attached earlobes is 2/3 = 0.66667

the probability of having both = 0.6667*0.66667 = 0.4445

6 0

3 years ago