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sineoko [7]
3 years ago
13

Which equation is the equation of a line that passes through -10 ,3 and is a perpendicular to Y equals 5X -7

Mathematics
1 answer:
laiz [17]3 years ago
3 0
The slope perpendicular to the one given is the opposite reciprocal.  So the slope of the "new" line will be -1/5.  Using y = mx + b and filling in 3 for y, -10 for x and the slope, m, of -1/5 will help you solve for b.  Then use that b to write the new equation.  3= -1/5(-10) + b and b = 1.  Your equation, then, is y = -1/5x + 1
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2cos²x+cos x-1=0

cos x=t

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First set solutions.
t₁=(-1-3)/2=-4/4=-1   
cos x=-1  ⇒x=cos⁻¹ (-1)=π +2kπ    or     180º+360ºk    (k=(...-2,-1,0,1,2...)

Second set solutions:
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cos x=1/2  ⇒ x=cos⁻¹ 1/2=π/3+2kπ   U   5π/3+ 2kπ   or
60º+360ºK  U 300º+360ºK        (k=...-2,-1,0,1,2,...)

solutions: first set solutions U second set solutions:

Answer in radians : π +2kπ U π/3+2kπ U 5π/3+ 2kπ   (k=...-1,0,1,...)
Answer is degrees: 180º+360ºk U 60º+360ºK  U 300º+360ºK        (k=...-2,-1,0,1,2,...)
4 0
3 years ago
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