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Masja [62]
3 years ago
7

Find the ratio of the following geometric sequences

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0

Answer:

A: 2

B: -1/3

Step-by-step explanation:

A: We are looking for the common ratio between the terms of the sequence, which is essentially what you are multiplying by to get from one term to the next. To find this, we just have to divide the second term by the first term.

-4 / -2 = 2, therefore our common ratio is 2.

We can check this by continuing to multiply the next terms by 2 - -4 x 2 = -8, -8 x 2 = -16, so the pattern works.

B: For B, we will do exactly the same method as before:  3/-9 = -1/3, so our multiplier is -1/3.

To check: 3 x -1/3 = -1, and -1 x -1/3 = 1/3, which both follow our rule.

Hope this helps! Let me know if you have any questions.

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den301095 [7]
By the rules of secants, 50° is half the sum of 20° and x.
  50° = (20° + x)/2
  100° = 20° + x
  80° = x
6 0
4 years ago
BRAIN LIST TO THE ONE THAT GET THE ANSWER RIGHT :D PLEASE HELP ME
vitfil [10]
The range is the difference between the highest and lowest number.

So the lowest number on this box plot is 5 and the highest is 15, so we will find the difference between them.

15 - 5 = 10. 

So the answer to your question should be : 10. 

It's easy really.. hope this helps :)
4 0
3 years ago
Read 2 more answers
1. What is the minimum number of vertices in a binary tree with height 5? What is the maximum number of vertices in a binary tre
Hunter-Best [27]

Answer:

Height = 5

Minimum number of vertices in a binary tree

whose height is h.

So, there must be  At least one node at each of first h levels.

Minimum number of vertices = h

So, Minimum number of vertices of height 5 is 5

The maximum number of nodes in a binary tree of height h = 2^{h+1}- 1

Substitute h = 5

The maximum number of nodes in a binary tree of height 5 = 2^{5+1}- 1

The maximum number of nodes in a binary tree of height 5 = 63

So, the maximum number of vertices in a binary tree with height 5 is 63

6 0
3 years ago
Two concentric circles are of radii 5 cm and 3 cm. Determine the length of the chord of the larger circle which touches the smal
tangare [24]

Answer:

Let O be the common center of two concentric circles and let AB be a chord of larger circle touching the smaller circle at P join OP

Since OP is the radius of the smaller circle to any chrod of the circle bisects the chord.

∴ AP=BP

In right ΔAPO we have

OA  

2

=AP  

2

+OP  

2

⇒25−9=AP  

2

 

⇒AP  

2

=16⇒AP=4

Now AB=2,AP=2×4=8[∵AP=PB]

hence the length of the chord of the larger circle which touches the smaller circle is 8cm.

Step-by-step explanation:

6 0
2 years ago
Can you help me. What is 2x-14
mylen [45]

Answer: 2(x-7)

Step-by-step explanation: 2x−14

2x−14

=2(x−7)

4 0
3 years ago
Read 2 more answers
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