If it’s for the App Store, follow this
Settings > ITunes & Apple Store > Password Settings > Turn off require password by pressing the swipe button thing. I’m sorry if this doesn’t help
Answer:
The program to this question can be given as follows:
Program:
#defining variable quarters, dimes, and nickels.
quarters=int(input("Enter value of quarters: ")) #input value by user dimes=int(input("Enter value of dimes: ")) #input value by user nickels=int(input("Enter value of nickels: ")) #input value by user
#defining variable pennies
pennies = ((25*quarters)+(10*dimes)+(5*nickels))
#calculate value in pennies variable
print('Total number of coins in pennies is: ',pennies)#print value
Output:
Enter value of quarters: 3
Enter value of dimes: 2
Enter value of nickels: 1
Total number of coins in pennies is: 100
Explanation:
In the above python program code, firstly three variable "quarters, dimes, and nickels", all of these variable uses input function, that is used to take input value from the user side, in these variable, an int is used that defined, that user input only integer value.
- After taking input from the user a new variable "pennies" is defined, which is uses the user input values and calculates its addition.
- In the next line, print function is used, which uses variable "pennies" to print its calculated value.
Creating a letter head is very simple. However, you need to do some planning. You are required to pick a size and shape accordingly. I would prefer a landscape oriented rectangle. Select a theme appropriate and consistent with the traits of you company. Personalize with a simple and sleek image that can be printed easily if necessary. Select a font that is bold enough, readable, and eye catching. You can include items like a slogan, a name, phone numbers, address, email address, a link to you web address and the established dates.
Answer:
def odd_even(N):
for number in range(0, N+1):
if number % 2 == 0:
print(str(number) + " is even")
elif number % 2 == 1:
print(str(number) +" is odd")
odd_even(5)
Explanation:
- Create a method called odd_even that takes one parameter, N
- Initialize a for loop that iterates through 0 to N
Inside the loop, check if module of the number with respect to 2 is equal to 0. If yes, print it as even number. If module of the number with respect to 2 is equal to 1, print it as odd number
Call the method
