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romanna [79]
3 years ago
12

Can anybody help me plz

Mathematics
2 answers:
klio [65]3 years ago
6 0
Circumference formula is C=2 x 3.14 x radius

Radius in this case is 5 because it’s half of 10.
Multiply it all together and you should get C= 31.4
Alja [10]3 years ago
4 0
You do 3.14×diameter... the diameter in this case is 10
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Arrange the hyperbolas in increasing order of the horizontal widths of their asymptote rectangles.
almond37 [142]

The  increasing order of the horizontal widths of their asymptote rectangles is dependent on the values gotten from  y = ± x.

<h3>What is a Hyperbola?</h3>

This is defined as a two-branched open curve formed by the intersection of a plane perpendicular to the bases of a double cone.

The rectangular hyperbola has two asymptotes which are defined as y = ± x in this scenario.

Read more about Hyperbola here brainly.com/question/3351710

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2 years ago
4 cm<br>3 cm<br>x cm<br>area = 19 cm2​
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8 0
3 years ago
Read 2 more answers
How do I solve this problem?
nexus9112 [7]
Subtract the second equation from the first equation.
x = -1
Plug -1 back in to either equation and solve for y.
3(-1) + y =-10
-3 + y = -10
Add 3 to both sides
y = -7
CHECK
3(-1) -7 = -10
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5 0
4 years ago
In my town, gas prices are always listed to the thousandths place. Since the smallest coin we have is the penny, we have to roun
tangare [24]

Answer:

<h2>  $8.16</h2>

Step-by-step explanation:

given the amount $8.162

if we are to round this amount to the nearest hundredth, we would have

$8.16

this is because will have already consider the last value in the given digit and this value is not up to 5  hence we are not able to round the number next to it up, but we have to retain its current value of 6.

therefore the value is

$8.16

8 0
3 years ago
The value of V8 is between which two integers?<br> 7 and 9<br> 49 and 81<br> 2 and 3<br> 3 and 4
nekit [7.7K]

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\sqrt{4}  <  \sqrt{8}  <  \sqrt{9}

Thus :

2 <  \sqrt{8}  < 3

So √8 is between 2 and 3 ,

Which means option three is the correct answer.

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8 0
3 years ago
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