Answer:
<h3>The answer is (-34.125)</h3>
Answer:
Since we have a^7 on the Numerator and after simplification... No "a" was left in the expression. It simply means that all a's in the numerator was eliminated and 2a's were left in the denominator.
To eliminate a^7 and still have 2a's as a remainder in the denominator... 'n' must be equal to 9
So
n=9
The bus stop method is just like division.
Ex
137÷5=
1.) 5 goes into one zero times so there is a zero on top.
2.) 5 goes into 13 two times, so after the zero there is a 2.
3.) 5 goes into 37 seven times so there is a 7 after the 2.
4.) There is a 2 left and five can't go into school therefore that is a remainder.
027R2
5/137
<u>- 10</u>
37
<u>-35</u>
2
Hoped I helped:D
Answer:
So angle 3 is congruent to angle 4 because they are both complimentary to 1 and 2.
By SAS, triangle SNM is congruent to triangle SNF.
By CPCTC, angle QMN is congruent to angle RFN.
By AAS, triangle QMN is congruent to RNF.
So by CPCTC, QM=RP