Answer:
The correct answer is option B.
Explanation:
FRAP or Fluorescence Recovery After Photobleaching refers to a method of finding the kinetics of diffusion in living cells, generally with the assistance of fluorescence microscopy. The method comprises the labeling of a particular cell constituent with a fluorescent molecule, imaging that cell, photobleach a small section of the cell, then image the recovery of fluorescence with time.
In the given question, as the fluorescence has recovered back to the bleached region. The scientist can come to the conclusion that the membrane of the cell and the peripheral membrane proteins do not always belong together.
4 mps increase in 10 seconds = 2 mps increase in 5 seconds = .4meters/2sec
Answer:
Yes, they are!
Explanation:
While inhabiting marshy areas, the Balaeniceps rex is found to be both a secondary and tertiary consumer preying on fish ranging in size from that of Large Mouth Bass to the small Pacific Herring, and other aquatic organisms such as frogs similar to the Red Eyed Tree Frog
<h2>
Answer:</h2>
The scientist started to study relationships among various groups of organisms <u>C. by using genetic analyses</u>.
<h2>
Explanation:</h2>
The following features were used to study about the relationships between different groups of organism:
- External morphology
- Similarities in structure
- Genetic analysis
- Chemical composition
The molecular similarities in the structure of RNA, DNA, and proteins help to establish the relationship of relationships between different groups of organisms. This was studied through testing the samples obtained by organisms using genetic analyses.
Answer:
<h2>e) 3/4
</h2>
Explanation:
As given;
Black (B) is dominant over red (b), so B is dominant over b.
Solid (S) is dominant over spotted color(s), so S is dominant over s.
Offspring of BBss and bbss individuals are:
Gametes of parent BBss are Bs, Bs and gamete of bbss are bs, bs
offspring are : all Bbss
Cross between these offspring is; Bbss×Bbss
Gametes of parent Bbss are: Bs and bs as given that the genes are linked.
Bs, bs × Bb, bs
Offspring are = BBss, Bbss, Bbss, bbss
Black spotted (B_ss) = 3/4
