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ki77a [65]
2 years ago
5

T = 2π √l/g Re-arrange to make l the subject.

Mathematics
1 answer:
zhuklara [117]2 years ago
5 0
T = 2 \pi \sqrt{ \frac{l}{g}}
\frac{T}{2 \pi} = \sqrt{ \frac{l}{g}}
( \frac{T}{2 \pi} )^{2} = \frac{l}{g}
l = g \times ( \frac{T}{2 \pi} )^{2}
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