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ki77a [65]
3 years ago
5

T = 2π √l/g Re-arrange to make l the subject.

Mathematics
1 answer:
zhuklara [117]3 years ago
5 0
T = 2 \pi \sqrt{ \frac{l}{g}}
\frac{T}{2 \pi} = \sqrt{ \frac{l}{g}}
( \frac{T}{2 \pi} )^{2} = \frac{l}{g}
l = g \times ( \frac{T}{2 \pi} )^{2}
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HELP asap AB=85m Find the length of Line CD
Aleks [24]
CD = x
BC = y
AB = 85
BD = BC+CD = y+x

tan(angle) = opposite/adjacent
tan(28) = BC/AB
tan(28) = y/85
85*tan(28) = y
y = 85*tan(28)
y = 45.1953016912257

tan(angle) = opposite/adjacent
tan(31) = BD/AB
tan(31) = (y+x)/85
tan(31) = (45.1953016912257+x)/85
85*tan(31) = 45.1953016912257+x
51.0731526173427 = 45.1953016912257+x
51.0731526173427-45.1953016912257 = 45.1953016912257+x-45.1953016912257
5.877850926117 = x
x = 5.877850926117

So CD is roughly 5.877850926117 meters

8 0
3 years ago
Solve the inequality for x<br> 3^(6x+18)&lt;27^(3x)
Lera25 [3.4K]

Answer:

\displaystyle x > 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

<u>Algebra II</u>

  • Exponential Rule [Powering]: \displaystyle (b^m)^n = b^{m \cdot n}
  • Solving exponential equations

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle 3^{6x + 18} < 27^{3x}<em />

<em />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Rewrite:                                                                                                             \displaystyle 3^{6x + 18} < 3^{3(3x)}
  2. Set:                                                                                                                     \displaystyle 6x + 18 < 3(3x)
  3. Factor:                                                                                                               \displaystyle 3(2x + 6) < 3(3x)
  4. [Division Property of Equality] Divide 3 on both sides:                                  \displaystyle 2x + 6 < 3x
  5. [Subtraction Property of Equality] Subtract 3x on both sides:                       \displaystyle -x + 6 < 0
  6. [Subtraction Property of Equality] Subtract 6 on both sides:                        \displaystyle -x < -6
  7. [Division Property of Equality] Divide -1 on both sides:                                 \displaystyle x > 6
8 0
3 years ago
Read 2 more answers
Look at the figure which step should be taken next to construct a line parallel to AB
FinnZ [79.3K]
My answer is the 2nd option.

Without changing the compass setting from the previous step, place the compass on point P. Draw an arc similar to the one already drawn.

Parallel lines are lines that do not meet. In this figure, point P is the point where the 2nd line can be drawn and become parallel to line AB. 
8 0
3 years ago
What is a correct congruence statement for the triangles shown?<br> Enter your answer in the box.
Nesterboy [21]

Answer:

ASA

Step-by-step explanation:

there are two congruent angles with an included side in between

6 0
1 year ago
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At an auditorium, 3 1/2 sections are filled with people watching a play. Exactly 3/5 of the people watching the play are parents
worty [1.4K]

Answer:

Fraction[Total number of sections filled filled with parents] = 2¹/₁₀ section

Step-by-step explanation:

Given:

Total number of sections filled = 3¹/₂ = 7 / 2 sections

Number of fraction parents watching play = 3/5

Find:

Fraction[Total number of sections filled filled with parents]

Computation:

Fraction[Total number of sections filled filled with parents] = Total number of sections filled x Number of fraction parents watching play

Fraction[Total number of sections filled filled with parents] = [7/2] x [3/5]

Fraction[Total number of sections filled filled with parents] = 21 / 10 sections

Fraction[Total number of sections filled filled with parents] = 2¹/₁₀ section

5 0
3 years ago
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