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2 years ago

T = 2π √l/g Re-arrange to make l the subject.

1 answer:

5 0

$T = 2 \pi \sqrt{ \frac{l}{g}}$
$\frac{T}{2 \pi} = \sqrt{ \frac{l}{g}}$
$( \frac{T}{2 \pi} )^{2} = \frac{l}{g}$
$l = g \times ( \frac{T}{2 \pi} )^{2}$

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Answer:

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Step-by-step explanation:

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The sum of two polynomials is â€"yz2 â€" 3z2 â€" 4y 4. If one of the polynomials is y â€" 4yz2 â€" 3, what is the other polynomi

gtnhenbr [62]

The sum of polynomials involves adding the polynomials

The other polynomial is $y^3 -y^2+ 4y - 1$

The sum of the polynomials is given as:

$Sum = y^3 + 3y^2 + 4y - 4$

One of the polynomials is given as:

$P = 4y^2 - 3$

Represent the other polynomial with Q.

So, we have:

$P +Q =Sum$

Substitute the expressions for P and Sum

$4y^2 - 3 +Q =y^3 + 3y^2 + 4y - 4$

Make Q the subject

$Q =y^3 + 3y^2 -4y^2+ 4y - 4 +3$

Evaluate like terms

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Hence, the other polynomial is $y^3 -y^2+ 4y - 1$